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Anastaziya [24]
3 years ago
7

A truck can be rented from Company A for ​$70 a day plus ​$0.20 per mile. Company B charges ​$20 a day plus ​$0.40 per mile to r

ent the same truck. How many miles must be driven in a day to make the rental cost for Company A a better deal than Company​ B's?
For Company A to have a better​ deal, the truck must be driven more than

blank miles per day.

pls fast
Mathematics
1 answer:
Otrada [13]3 years ago
8 0

Answer:

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

Step-by-step explanation:

Given that:

Rent per day of company A = $70

Per mile charges = $0.20

Let,

x be the number of miles.

A(x) = 0.20x + 70

Rent per day of company B = $20

Per mile charges = $0.40

B(x) = 0.40x + 20

For make Company A better deal,

A(x) > B(x)

0.20x+70 > 0.40+20

0.20x-0.40x>20-70

-0.20x>-50

Dividing both sides by -0.20

\frac{-0.20x}{-0.20}>\frac{-50}{-0.20}\\x>250

Hence,

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

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If the measure of 1 is x and the measure of <2 is x+50, what is the measure of <4?
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Step-by-step explanation:

First, we want to find the measure of angle 2, because the measure of angle 2 is equal to angle 4. When 2 straight lines cross each other, the angles formed are always equal to the angle right across from it.

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