Answer:
Some of the other answers are good examples of solving a system of three equations in three unknowns, which is what this problem is asking. Though the simplest way to solve this problem is actually to notice that, if we sum the three equations, we get:
X + Y = 10
X + Z = 20
+ Y + Z = 24
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2X + 2Y + 2Z = 54
Factoring out the 2, we have 2(X + Y + Z) = 54, and dividing both sides by 2 reveals that X + Y + Z = 27.
Step-by-step explanation:
hopefully this helps
The answer to the first part is (4,1).
The answer to the second part is (11,2).
Answer:
The answer is <u>D: lll and IV only</u>
Step-by-step explanation:
He bought 45 bars of chocolate.
1/5 x 45 = 9
He ate 9 bars on Tuesday.
45 - 9 = 36
He had 36 bars left.
1/12 x 36 = 3
He ate 3 bars on Wednesday
36 - 3 = 33
He had 33 bars left.
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Answer: He had 33 bars left.
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