Answer:
The height of the water = 6.2 in. to the nearest tenth
Step-by-step explanation:
∵ The rate of flows of water into the tank = 8000 in.³/min.
∴ The volume of the water in the tank after 10 min. = 8000 × 10 = 80000 in.³
∵ The water take the shape of the tank
∴ The height of the water = volume of water ÷ Area of the base of the tank
∵ The tank is cylinder with diameter 128 in. and height 72 in.
∴ The area of the base of the tank = π(128/2)²
∴ The height of the water = 
∴ The height of the water = 6.2 in. to the nearest tenth
Answer:
It is all determined by how many spaces and which way the decimal point moves.
Step-by-step explanation:
So here are two examples
<em>Example 1:</em>
500000.00
To write this in scientific notation you would move the decimal place to the left.
You would move it 5 digits to the left so the exponent of 10 would be 5
<em>Example 2</em>
0.0000042
Here to write this in scientific notation you move the decimal place to the right.
You would move it 6 digits to the right so the exponent would be -6
Answer:
Volume = V= 346.43 cm ^3
Step-by-step explanation:
15.32 x 10 = 153.2cm Area of side
We find the height of the cylinder, to enable the radius/2 for the circle side x 2
it would be the same as triangle side 6 but the exact circumference is worked out at 6.37
We start by finding the side
As a = half circumference = 20 x sin (30) =10 we x2 for full circumference, then divide by pi
10 +10 =20cm circumference.
20/6.28 =3.1847133758 = radius
we x 2 and find the height
3.1847133758 x 2 = 6.3694267516
rounded to nearest 10th = 6.4 units exact 6.37
We find other measurements before calculating volume.
and b = √400-√100 = √300
b= 17.32 (height for volume use) or length of right side cylinder
c= 20 hypotenuse.
Volume = πr2h
V= 3.14 * 6.37 * 17.32 =346.43
V= 346.43 cm ^3
V= 346 cm ^3 to nearest 10th
V= 346.43 cm^3
The volume of the shaded region is 1650 cubic feet.
Answer:
Because of the logarithmic basis of the scale, each whole number increase in magnitude represents a tenfold increase in measured amplitude; in terms of energy, each whole number increase corresponds to an increase of about 31.6 times the amount of energy released, and each increase of 0.2 corresponds to approximately a doubling of the energy released.
Step-by-step explanation:
