Answer:
2 rides & 4 games
Step-by-step explanation:
2 rides=$8
4 games=$8
8+8=$16
There are 4 cards with a picture of a rose and 3 cards with a picture of a daisy.
After one rose card is removed, the remaining cards are 3 cards with a picture of a rose and 3 cards with a picture of a daisy. A card is chosen at random,
the probability that the chosen card has rose on it is
.
The correct choice is (A).
The right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
Let be an <em>exponential</em> function of the form
, where
and
are <em>real</em> numbers. A <em>horizontal</em> asymptote exists when
, which occurs for
.
For this function, the <em>horizontal</em> asymptote is represented by
and to change the value of the asymptote we must add the <em>parent</em> function by another <em>real</em> number (
), that is to say:
(1)
In this case, we must use
to obtain an horizontal asymptote of -3. Thus, the right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280
Answer:
36 years old
Step-by-step explanation:
let x = age of Rachael
2x+3 = current ages combined
[(2x+3)+4]+4 = 75
2x+11 = 75
2x = 75-11
2x = 64
x = 32
Rachel is 32 years old. Isaac is 3 years older, which is 35 years old.
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Answer:
0.91517
Step-by-step explanation:
Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.
Let A - the event passing in SAT with atleast 1500
B - getting award i.e getting atleast 1350
Required probability = P(B/A)
= P(X>1500)/P(X>1350)
X is N (1100, 200)
Corresponding Z score = 
