Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.
Step-by-step explanation:
20*282= 5640
10680-5640=5040
50-20=30
5040 dividend by 30= 168
Answer: 168
Answer:
4/6
Step-by-step explanation:
you multiply until both numbers have the same denominator so 1/7 times 6/6 equals 6/42 and multiply 4/6 times 7/7 it would be 28/42 so the answer would be that 4/6 is greater.
Answer:
38m and 90cm
1m = 100cm
3890cm = 38m and 90cm
Step-by-step explanation:
1m = 100cm
3890cm = 38m and 90cm
Answer:
0.000025
Step-by-step explanation:
the difference between225-180=45
so the percentage= 45×100/100
=0.45%
as the instruction say=0.45%/180
=0.0045/180
=45/1800000
=0.000025
