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Vusi makes bead bracelets in different designs. The first design uses 23 beads, the second design uses 29 beads and the third de

sergey [27]

When the remainder theorem is applied to the total number of beads, the number of beads left is 3

<h3>What is remainder theorem?</h3>

The question is an illustration of remainder theorem. Remainder theorem is used to determine the remainder when a number divides another

The number of beads used in each design are given as:

$First = 23$

$Second = 29$

$Third = 31$

Calculate the total number of beads used for all three designs

$Total =First + Second + Third$

$Total =23 + 29 + 31$

$Total =83$

The number of available beads is:

$Available = 750$

Divide 750 by 83, to get the total number of designs

$n = \frac{750}{83}$

$n =9.03$

Remove decimal (do not approximate)

$n = 9$

The number of beads remaining is calculated using:

$Remaining =Available -n \times Total$

$Remaining =750 -9 \times 83$

$Remaining =3$

Hence, there are 3 beads remaining

Read more about remainder theorem at:

brainly.com/question/13328536

7 0

2 years ago

Consider the following system of equations:

Nadusha1986 [10]

The right answer for the question that is being asked and shown above is that: "Lines y = –2x + 3 and y = 3x – 5 intersect the y-axis." The description best describes the solution to the system of equations is that <span>Lines y = –2x + 3 and y = 3x – 5 intersect the y-axis</span>

8 0

3 years ago

Read 2 more answers

Pls pls pls answer! I will mark brainliest!!!! tysm<br> xy = 72<br> (x + 2)(y - 4) = 128

zheka24 [161]

Answer:

x=2 and y=36

Step-by-step explanation:

you have two equations

1) xy=72 and 2) (x+2)(y-4)=128

solve for one of the variables in equation 2), lets do y

(x+2)(y-4)=128, divide by (x+2) to both sides and add 4 to isolate variable y

therefore, y=(128/(x+2))+4

then plug in y into equation 1)

so x(our new y)=72

x( 128/(x+2) +4 )=72

distribute the x so you will get

(128/(x+2))x +4x=72

we are now solving for x, so isolate the x by subtracting 4x and multiplying by (x+2) to get

128x=(x+2)(72-4x)

multiply by distribution and combine like terms

-4x^2 -64x +144 =0

solve for x by quadratic formula, you'll get x=2 or x=-18

substitute back into equation 1), (2)(y)=72, solve for y to get 36

then you can check by substituting back into equation 2)

(2+2)(36-4)=128

(4)(32)=128, 128=128

6 0

2 years ago

How can I solve 4x+6y+5y+6y

Ede4ka [16]

That's not an equation, and it doesn't ask any question. As it stands, there's nothing to "solve".

You may have been given an assignment to "simplify" it ... make it prettier and less complicated.

In order to do that, let's pretend for a moment that you're asked to add up a list that says:

4 chickens + 6 cows + 5 cows + 6 cows

I'm convinced that you would have no trouble at all adding up this list. You would
know right away that you can add up all the cows into one number, but you can't
add cows to chickens. You would simplify the list,and it would become <em>

4 chickens + 17 cows</em>.

And now that you understand that, you're all ready to simplify the expression
in your question. Just add up all the 'y's into a single number, but you can't
add 'y's to 'x's.

When you're done, you have 4x + 17y, and you're done. That's all you can do with it.

7 0

3 years ago

A simple random sample of 28 Lego sets is obtained and the number of pieces in each set was counted.The sample has a standard de

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

Given that:

A simple random sample n = 28

sample standard deviation S = 12.65

standard deviation $\sigma$ = 11.53

Level of significance ∝ = 0.05

The objective is to test the claim that the number of pieces in a set has a standard deviation different from 11.53.

The null hypothesis and the alternative hypothesis can be computed as follows:

Null hypothesis:

$H_0: \sigma^2 = \sigma_0^2$

Alternative hypothesis:

$H_1: \sigma^2 \neq \sigma_0^2$

The test statistics can be determined by using the following formula in order to test if the claim is statistically significant or not.

$X_0^2 = \dfrac{(n-1)S^2}{\sigma_0^2}$

$X_0^2 = \dfrac{(28-1)(12.65)^2}{(11.53)^2}$

$X_0^2 = \dfrac{(27)(160.0225)}{132.9409}$

$X_0^2 = \dfrac{4320.6075}{132.9409}$

$X_0^2 = 32.5002125$

$X^2_{1- \alpha/2 , df} = X^2_{1- 0.05/2 , n-1}$

$X^2_{1- \alpha/2 , df} = X^2_{1- 0.025 , 28-1}$

From the chi-square probabilities table at 0.975 and degree of freedom 27;

$X^2_{0.975 , 27}$ = 14.573

$X^2_{\alpha/2 , df} = X^2_{ 0.05/2 , n-1}$

$X^2_{\alpha/2 , df} = X^2_{0.025 , 28-1}$

From the chi-square probabilities table at 0.975 and degree of freedom 27;

$X^2_{0.025 , 27}=$ 43.195

Decision Rule: To reject the null hypothesis if $X^2_0 \ > \ X^2_{\alpha/2 , df} \ \ \ or \ \ \ X^2_0 \ < \ X^2_{1- \alpha/2 , df}$ ; otherwise , do not reject the null hypothesis:

The rejection region is $X^2_0 \ > 43.195 \ \ \ or \ \ \ X^2_0 \ < \ 14.573$

Conclusion:

We fail to reject the null hypothesis since test statistic value 32.5002125 lies between 14.573 and 43.195.

6 0

2 years ago

What you have learned from thos topic​

What you have learned from thos topic