You, newton, and Descartes volunteer this summer. You have 2 times as many volunteer min as newton and Descartes. You all have 5040 volunteer min altogether. how many min do you volunteer?

Answer:

2520 volunteer minutes

Step-by-step explanation:

You have 2 times as many volunteer minutes as Newton and Descartes.

Now, if Newton and Descartes each have x volunteer minutes, it means you have 2x volunteer minutes.

Since the total volunteer minutes of the 3 of you is 5040,then we have;

2x + x + x = 5040

4x = 5040

x = 5040/4

x = 1260

Since you have 2x volunteer minutes, then you have: 2 × 1260 = 2520 volunteer minutes

4 0

3 years ago

Please open the image and help me

Kay [80]

Looks like

$y=2\sqrt[3]{x}+\dfrac1{x^2}+\pi$

Write $\sqrt[3]{x}$ as a fractional power, $x^{1/3}$ . This makes it more obvious that the power rule should be used here.

$y'=(2x^{1/3})'+(x^{-2})'+\pi'$

$y'=\dfrac23x^{-2/3}-2x^{-3}$

$y'=\dfrac2{3\sqrt[3]{x^2}}-\dfrac2{x^3}$

$y=(\sin(2x)+\tan(3x))^e$

Power and chain rule:

$y'=\left((\sin(2x)+\tan(3x))^e\right)'$

$y'=e(\sin(2x)+\tan(3x))^{e-1}(\sin(2x)+\tan(3x))'$

$y'=e(\sin(2x)+\tan(3x))^{e-1}(\cos(2x)(2x)'+\sec^2(3x)(3x)')$

$y'=e(\sin(2x)+\tan(3x))^{e-1}(2\cos(2x)+3\sec^2(3x))$

8 0

3 years ago