It is the extent to which a distribution is stretched
Answer:
x = 26
Step-by-step explanation:
because JKL is 90 degrees
x+8 + 2x+4 =90
3x + 12 =90
3x = 78
x = 26
Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
Answer:
50 27.5
50.01 27.5055
50.02 27.511
50.03 27.5165
Step-by-step explanation:
Answer:
<u>Option A. about 1 seconds</u>
Step-by-step explanation:
Let the initial speed u and the final speed v
Time t , distance s and acceleration of gravity g
The equation of motion are:
v = u + gt ⇒(1)
s = ut + 0.5 gt² ⇒(2)
v² = u² + 2gs ⇒(3)
Marques drops a plate from a height of 5 feet.
So, u = 0 , s = 5 ft , g = 9.8 m/sec²
Substitute at (2)
s = ut + 0.5 gt²
5 = 0 * t + 0.5 * 10 * t²
∴ t² = 5/(0.5*9.8) = 1.02
∴ t = √1.02 = 1.01 seconds ≈ 1 seconds (to the nearest integer)
<u>The answer is option A. about 1 seconds</u>
