<u>Answer-</u>
<em>The interval where the function is diffrentiable is </em>
![[-\infty,1)\ \bigcup\ (1,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C1%29%5C%20%5Cbigcup%5C%20%281%2C%5Cinfty%5D)
<u>Solution-</u>
The given expression is,
The function will be differentiable where it is continuous and it will not be differentiable, where the function is not continuous.
The function continuous everywhere except at x = 1, because
at x = 1, its limit does not exist.
Therefore, apart from x=1, this function is differentiable everywhere. The interval will be
I hate questions like this. It's like wishing for more wishes.
U add 6 to every number each time
5,11,17,23,29,35,41,47,53,59,65,71,78,84,90,96,101,108
108 is the 18th term
Answer:
-2?
Step-by-step explanation:
Multiply -1 by -4 to get 4
subtract 20 from 12 to get -8
simplify to get -2
Answer:
A haircut costs $31
Coloring hair costs $93
Step-by-step explanation:
h = haircut
c = color
First equation: 1h + 2c = 217
Second equation: 2h + 1c = 155
Solve using elimination:
First, multiply both the equations so that they cancel the h's out:
First equation:
-1(2h + 1c = 155)
-2h - 1c = -155
Second equation:
2(1h + 2c = 217)
2h + 4c = 434
Then, put the equations together, and solve:
2h + 4c = 434
-2h - 1c = -155
3c = 279
c = 93
Find h:
2h + 1c = 155
2h + 1(93) = 155
2h + 93 = 155
2h = 62
h = 31
Hope this helped!
