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elena-14-01-66 [18.8K]
3 years ago
6

If A and B are matrices of the same order, then

Mathematics
2 answers:
masha68 [24]3 years ago
3 0

Answer:

equal to

not equal to

Step-by-step explanation:

If A and B are matrices of the same order, then

cA + cB is equal to c(B + A)

cA - cB is not equal to c(B-A)

V125BC [204]3 years ago
3 0

Answer: The above answer is correct.

Step-by-step explanation: I got this correct on edmentum.

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Gemiola [76]

Answer:

You need more information to graaph this.

Step-by-step explanation:

6 0
3 years ago
What is the function that defines the following sequence? 10, 12, 14, 16, 18…
Furkat [3]

The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

<h3>How to define the function behind a sequence</h3>

Sequences are sets of elements characterized by at least a rule. In this case, the sequence shown is characterized by a function that generates even numbers equal or greater than 10. The function behind the sequence is shown below:

s = 10 + 2 · (n - 1)     (1)

Where n is the <em>element</em> index.

The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

To learn more on sequences: brainly.com/question/21961097

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4 0
2 years ago
Needs help answering
konstantin123 [22]

Answer:

26

Step-by-step explanation:

the answer is 26

6 0
2 years ago
(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t&lt;00≤t&lt;11≤t&lt;7t≥7;f(t)={0,t&lt;0−5,0≤t&lt;1−6,1≤t&lt;76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
f(t)\equiv-5u(t)-u(t-1)+12u(t-7)
5 0
3 years ago
29.25 is what percent of 78
Alexus [3.1K]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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