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Murrr4er [49]
3 years ago
14

Are the two triangles​ congruent? If​ so, write the congruence statement.

Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0

Answer:

E

Step-by-step explanation:

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Your new TV screen has a width that is 4 inches longer than its height. If the screen's diagonal measurement is 20 inches, find
scoundrel [369]

Answer:

So the height is 12

Step-by-step explanation:

Let W be the width

Let W- 4 be the height

W2 +(W-4)2 = 400

So: W2 -4W-192 =0

One uses the quadratic solution:

W = (4 + (16 + 4*192).5)/2 = 16

7 0
4 years ago
A case of water costs $3.84 and contains 24 bottles of water. Determine the cost of each bottle of water.
Darya [45]

Answer:

0.16

Step-by-step explanation:

3.84/24=0.16

Divide the total price by the amount of waterbottles in the case to find each individual one.

Hope this helps!

3 0
3 years ago
The square of a number x is 92. The number x is between what two consecutive whole numbers?
natta225 [31]
The number X is placed somewhere between 9 and 10. That's because 9 squared is 81 and 10 squared is 100.
5 0
3 years ago
Solve 7x-9=28+4(x-1)
ANEK [815]
I got 10.333333333333
8 0
4 years ago
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0
3 years ago
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