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asambeis [7]
3 years ago
14

What is the constant of variation for the relationship f(x)=30x

Mathematics
2 answers:
gregori [183]3 years ago
7 0

Since the equation can be written in the form  y = kx ,  y  varies directly with  x  and  k . The constant of variation,  k , is  30 .

30

elixir [45]3 years ago
3 0
B)30.................
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Quadrilateral DEFG has vertices D(−2,4) , E(4,7) , F(10,3) , and G(8,0) .
fredd [130]

A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:

(x,y)→(y,-x).

Then:

  • D(−2,4)→D'(4,2)
  • E(4,7)→E'(7,-4)
  • F(10,3)→F'(3,-10)
  • G(8,0)→G'(0,-8)

Answer: the coordinates of vertices of quadrilateral D′E′F′G′ are D'(4,2), E'(7,-4), F'(3,-10), G'(0,-8).

8 0
3 years ago
5x + 5 equals 16 - 6x​
bulgar [2K]

Answer:x=1

Step-by-step explanation:

5 0
3 years ago
The temperature in degrees Celsius can be determined using the expression 5 9 (F – 32) where F is the temperature in degrees Fah
Norma-Jean [14]

Answer:

The temperature on Celsius scale for 86 ºF is 30 ºC.

Step-by-step explanation:

Both degrees Celsius and Fahrenheit are relative scales of temperature. The relationship between degrees Fahrenheit and degrees Celsius is summarized by the equation below:

T_{C} = \frac{5}{9}\cdot (T_{F}-32) (1)

Where:

T_{F} - Temperature, measured in degrees Fahrenheit.

T_{C} - Temperature, measured in degrees Celsius.

If we know that T_{F} = 86\,^{\circ}F, then its equivalent temperature on Celsius scale is:

T_{C} = \frac{5}{9}\cdot (86-32)

T_{C} = 30\,^{\circ}C

The temperature on Celsius scale for 86 ºF is 30 ºC.

3 0
3 years ago
Find an equation of the line containing (-3,4) and having slope -2. If this line contains the points (a,8) and (5,b), find a and
larisa [96]

Answer:

Step-by-step explanation:

Remark

The slope intercept line is written as y = mx + b in it's general form.

You can get the slope, m, immediately because it is given as -2

So far what you have is y = -2x + b

y intercept

To get the y intercept, use the point (-3 , 4)

x = - 3

y = 4

4 = -2*(-3) + b

4 = 6 + b                 Subtract 6 from both sides

4 - 6 = 6-6 + b

b = - 2

Line

y = -2x - 2

(a,8)

y = -2a - 2

8 = -2a - 2              Add 2 to both sides

8 +2 = -2a -2+2     Combine

10 = - 2a                 Divide by - 2

10/-2 = a

a = -5

(5,b)

y = -2x - 2

x = 5

y = b

b = -2*5 - 2

b = -10 - 2

b = - 12

6 0
3 years ago
if a square with point H at coordinates (-8,5) was reflected across the y-axis, what would the coordinates of point H' be ?
zimovet [89]

Answer:

Your answer would be 8 and 5 because you are just moving the point over the y axis from -8 and 5 to 8 and 5.

Step-by-step explanation:


6 0
3 years ago
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