All categories

3 years ago

What is the area of the rhombus (figure only show one part of the diagonals)

Mathematics

1 answer:

Tomtit [17]3 years ago

5 0

Answer:

60 cm^2 (dark blue)

Step-by-step explanation:

Since a rhombus's diagonal bisect each other, the diagonal's full length is 10 and 12. From there the area is 10*12 / 2 which is 60

You might be interested in

There are five students wearing glasses. There are three more boys than girls wearing glasses. On your worksheet, solve the ques

Llana [10]

Answer:

Four boys and one girl.

Step-by-step explanation:

Total students wearing glasses = 5

Separate the students by x and x + 3. It is x + 3 for the boys because there are three more boys wearing glasses.

Girls = x

Boys = x + 3

Total = 5

Calculate:

x + x + 3 =5

2x + 3 =5

2x = 2

x = 1

Boys wearing glasses = (1) + 3 = 4

Girls wearing glasses = 1

3 0

3 years ago

Seven line segments are shown on the coordinate plane.

Fittoniya [83]

Answer:

The possible images of AB are;

PN, HG, and CD

Step-by-step explanation:

The coordinates of the point A is (1, 2), the coordinates of the point B is (5, 2)

Therefore, the length of the line AB = 5 - 1 = 4 units

The given transformations are, reflections, rotations, and/or translations which are rigid transformations, such that the length of the image of AB will be the same as the length of AB

Therefore, the possible images of AB are;

PN with coordinates P(5, -2) and N(9, -2) and length 9 - 5 = 4 units

HG with coordinates H(-4, -4) and G(-4, -8) and length -4 - (-8) = -4 + 8 = 4 units

CD with coordinates C(-4, 6) and D(-4, 2) and length 6 - 2 = 4 units

4 0

3 years ago

Guys plz help me answer this !!!!

Stella [2.4K]

Answer: -1

Step-by-step explanation:

8-13=s+4s

-5=5s

-5/5=5s/5

-1=s

5 0

3 years ago

Read 2 more answers

Malachi bought a new fishing rod. The regular price of the fishing rod was $125.99. He bought it on sale with a 15% discount. Sa

stich3 [128]

If the discount is 15 percent, he still pays (100-15) or 85%

125.99 * 85%

125.99 * .85 = 107.09 is the price he pays for the rod

107.09 * .03 =3.21 is the sales tax

107.09+3.21=110.30 is the price of the rod with the discount and the tax

4 0

3 years ago

Read 2 more answers

A Statistics professor has observed that for several years students score an average of 114 points out of 150 on the semester ex

kirill [66]

Answer:

Reject $H_0$ . The change is statistically significant. The software does appear to improve exam scores.

Step-by-step explanation:

We are given that a Statistics professor has observed that for several years students score an average of 114 points out of 150 on the semester exam. The software is expensive, and the salesman offers to let the professor use it for a semester to see if the scores on the final exam increase significantly.

In the trial course that used this software, 218 students scored an average of 117 points on the final with a standard deviation of 8.7 points.

Let $\mu$ = mean scores on the final exam.

SO, Null Hypothesis, $H_0$ : $\mu \leq$ 114 points {means that the mean scores on the final exam does not increases after using software}

Alternate Hypothesis, $H_A$ : $\mu$ > 114 points {means that the mean scores on the final exam increase significantly after using software}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average points = 117 points

s = sample standard deviation = 8.7 points

n = sample of students = 218

So, test statistics = $\frac{117-114}{\frac{8.7}{\sqrt{218} } }$ ~ $t_2_1_7$

= 5.091

Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_2_1_7$ > 5.091) = Less than 0.05%

Since, in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, the t table gives critical value of 1.645 at 217 degree of freedom for right-tailed test. Since our test statistics is higher than the critical value of t as 5.091 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the change is statistically significant. The software does appear to improve exam scores.

3 0

3 years ago