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inysia [295]
3 years ago
11

Solve tangent 195 using sum and difference formula

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0
Idk I Would Fine The Answer To Your Question Now
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Identify which graph below contains the coordinate points (–3, 4),(–2, 0), and (0, –8). Select all that apply.
Aleks04 [339]

Answer:

A, C, D

Step-by-step explanation:

All of the plot curves contain (0, -8) and (-2, 0)

B doe NOT contain (-3, 4), though the plot lines seem kind of fuzzy and other curves may miss, but not by much.

5 0
2 years ago
Read 2 more answers
Y-1=5/6(x-4) in standard form
scoray [572]
           y - 1 = ⁵/₆(x - 4)
           y - 1 = ⁵/₆(x) - ⁵/₆(4)
           y - 1 = ⁵/₆x - 3¹/₃
             + 1         + 1
                 y = ⁵/₆x - 2¹/₃
        ⁻⁵/₆x + y = ⁵/₆x - ⁵/₆x - 2¹/₃
   -6(⁻⁵/₆x + y) = -6(-2¹/₃)
-6(⁻⁵/₆x) - 6(y) = 14
         5x - 6y = 14
8 0
2 years ago
Read 2 more answers
Anna has a 30-year, 5.75% mortgage on her $250,000 home. She has been
poizon [28]

Answer:

Her new monthly payment is now $1,378.91¢

Step-by-step explanation:

  For us to calculate the new monthly mortgage payment that Anna will start paying from now on, we need to input the formula for calculating monthly mortgage payments.

The formula is:-

          M = P [\frac{r(1+r)^{n} }{(1+r)^{n}-1}]

  Where M is the monthly mortgage payment.

              P is the principal

              r is the monthly interest rate calculated by dividing your annual interest rate by 12

             n is the number of payments(the number of months you will be paying the loan).

 In this case, the new principal that Anna must pay back is $231,905.47¢. The annual interest rate has been reduced to 5.17% from 5.75% so the new monthly interest rate will be obtained by dividing the new annual interest rate by 12

   = 5.17%/2

   = 0.431%

  This is the new monthly  interest rate.

  Since she has been paying her mortgage loan diligently for 5 complete years. It means she now has just 25 years to complete the payment. If 12 months make up one year, then there are - 12 × 25 = 300 more months to go.

   300 is therefore "n" that is required for the calculation.

All the terms needed for the calculation of her new monthly mortgage is now complete.

P = $231,905.47¢

r  = 0.431%

n = 300

             

 M = 231,905.47[\frac{0.00431(1+0.00431)^{300} }{(1+0.00431)^{300} -1}]

     = 231,905.47[\frac{0.00431(3.634)}{2.634}]

     = 231,905.47 × 0.005946

   M  = $1,378.91¢      

   Therefore her new monthly mortgage payment will become $1,378.91¢

4 0
3 years ago
Read 2 more answers
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
Ian invested $90,000 in an account paying an interest rate of 2.6% compounded quarterly. Assuming no deposits or withdrawals are
barxatty [35]

Answer:

A≈<u>107902</u>

Step-by-step explanation:

8 0
2 years ago
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