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koban [17]
2 years ago
10

PLEASE HELP!!! DUE TODAY

Mathematics
1 answer:
Maksim231197 [3]2 years ago
7 0

Answer:  The awnser is   4/15

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What is the range of the data shown on the stem-and-leaf plot? <br>93<br> 43 <br>50<br> 48
notsponge [240]

Answer: C) 50

Step-by-step explanation:

The smallest number on the plot is 43.  The largest is 93.  The range of a chart is the largest number - the smallest number.  Thus, simply do 93-43 to get 50.

Hope it helps <3

5 0
3 years ago
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How to solve this problem
shepuryov [24]
I cant tell if this is french or spanish but please translate so we can try to help you
3 0
3 years ago
1. The triangles above are similar. What is the ratio (larger to smaller) of the perimeters? (1 point)
eimsori [14]

Answer:

Ratio = 5/3

The ratio (larger to smaller) of the perimeters is 5/3

Step-by-step explanation:

Attached is an image of the two triangles.

Since both triangles are similar, the ratio of their perimeter is equal to the ratio of each similar sides.

Ratio = P1/P2 = S1/S2

Similar side for triangle 1 S1 = 15ft

Similar side for triangle 2 S2 = 9ft

Substituting the values;

Ratio = 15ft/9ft = 5/3

Ratio = 5/3

The ratio (larger to smaller) of the perimeters is 5/3

7 0
3 years ago
Help on number 7 please?​
Tpy6a [65]

Answer:

The average rate of change is 3

Step-by-step explanation:

0 to 5 is 5 in difference then the change on the next one: 1 to 9 the difference is 8 so the change is 3 and it increases by three on the rest of them.

  • (\) QueTooOfficial (/)
  • <em>officially out of brainly retirement</em>
7 0
3 years ago
Read 2 more answers
Help!!! I don’t get this :(
mafiozo [28]
You have to use distributive property. Multiply the numbers outside of the parenthesis by the numbers inside. For example, you would multiply 0.4 by 2x first, then multiply it by 1/2. You should get two answers. Write them down in this form: first answer + second answer. Then do the same for the other side of the equal sign, but leave the - 4 alone. If you need more help, let me know
7 0
3 years ago
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