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Dmitry_Shevchenko [17]

2 years ago

8

1. Find the next three in the sequence. 2,7,12,17

2 answers:

Svetradugi [14.3K]2 years ago

5 0

Answer:

n + 5

Step-by-step explanation:

n+5

2,7,12,17,22,27,32

bearhunter [10]2 years ago

4 0

Answer:

the next three terms are 2,7,12,17,22,27,32

have a nice day

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A conical paper cup has a radius of 2 inches. Approximate, to the nearest degree, the angle β so that the cone will have a volum

dezoksy [38]

Volume = area of base *height

20 = pir^2 *h

20 = 3,14*4*h

h = 20/12,56 = 1,59 rounded 1,6

- using the triangle formed by radius,the height of cup and the slant height of cup so we can writing that

tan ß = h/r so tan ß = 1,6/2 = 0,8

tan ß = 0,8 so ß = arctan 0,8 = 38,6 degrees so 39 degrees

hope helped

5 0

3 years ago

Ralph is an electrictian.he charges an initial fee of $32 plus $33 per hour. If Ralph earned $189 on a Job,how long did The Job

aleksley [76]

Answer:

5 hours

Step-by-step explanation:

189-32=157

157/33 is about 4.76

4.76 rounded is 5 so the job took 5 hours

6 0

3 years ago

Help me please ?!!!!

blondinia [14]

Answer:

<em>The slope of the line is -1</em>

Step-by-step explanation:

<u>Slope of a Line</u>

Suppose we know a given line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated as follows:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

From the table in the image, we select the points (1,4) (3,2). The slope is:

$\displaystyle m=\frac{2-4}{3-1}=\frac{-2}{2}=-1$

Now select two other points like (5,0) (7,-2)

$\displaystyle m=\frac{-2-0}{7-5}=\frac{-2}{2}=-1$

Following the same procedure with any other pair of points, we'll get the very same result:

The slope of the line is -1

4 0

3 years ago

Does anybody think they can help with this question?

Sati [7]

The perimeter of a square is the sum of all its sides' lengths

That means: perimeter =4*(7m+1)/3

5 0

3 years ago

1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the

Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

$\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I$

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

$f(x)=e^{3x}+\cos(5x),$

$g(x)=e^{3x}-\cos(5x),$

$h(x)=\cos(5x).$

Then, letting α = 1, β= -1 and ω = -2, we see that:

$\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.$

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0

3 years ago