Answer:
2 roots in every case, not all are real.
Step-by-step explanation:
All of these equations are quadratic equations (degree 2). Every quadratic has two roots. They may be identical (looks like 1 root), and they may be complex (zero real roots), but there are always 2 of them.
a) the y-value of the vertex is negative and the parabola opens downward (leading coefficient -5), so there are no real zeros and both roots are complex.
b) each binomial factor contributes a root. Both roots are real.
c) the discriminant is positive, (3²-4·2·1=1), so both roots are real.
Answer:

And solving we got:

We can find the sings of the second derivate on the following intervals:
Concave up
inflection point
Concave down
inflection point
Concave up
Step-by-step explanation:
For this case we have the following function:

We can find the first derivate and we got:

In order to find the concavity we can find the second derivate and we got:

We can set up this derivate equal to 0 and we got:

And solving we got:

We can find the sings of the second derivate on the following intervals:
Concave up
inflection point
Concave down
inflection point
Concave up
Yoy multiply 55 and 99 and get 5000 and than you times it an get your answer
Answer: x = 28
Step-by-step explanation:
x + 20=3x-36
20=2x-36
56=2x
56/2=28
So 28= x
Answer:
I can't see the ques
Step-by-step explanation:
Can u please post it again