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inna [77]
3 years ago
15

When full, a fuel tank holds 175 gallons of fuel. How many gallons of fuel are in the tank when it is 40% full?

Mathematics
2 answers:
gtnhenbr [62]3 years ago
8 0

Answer:

70 gallons

Step-by-step explanation:

kipiarov [429]3 years ago
6 0
The answer is 70 gallons full
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EB bisects ∠RED. Find the measure of ∠BED if ∠REB = 5x – 3 and ∠RED = 8x + 16<br><br>plzzzzzzzzzzz
Allushta [10]

Answer:

this is 52 degrees

Step-by-step explanation:

7 0
3 years ago
I need to find the image coordinates of the pre-image using reflection, and it has to be reflected over the line x=2. How do I s
Sladkaya [172]
The answer would be ( x+1, y+4)...... Hope this helps

5 0
3 years ago
Three more than 8 times a number is 29. Find the number.
yanalaym [24]
Well, first off, to solve for this, we can write the expression and then solve from there.
Expression: 8x + 3 = 29
So, now that we have our expression, we can solve for our missing number using the balancing method.
8x + 3 = 29
8x + 3 - 3 = 29 - 3 (we subtracted the three because we needed to get rid of the three on the left side of the equation do now we are just left with 8x = 26.
8x = 26
8x/8 = 26/8. (So, the 8 on the left side cancels out and we are just left with X.
X = 26/8
X = 13/4
X = 3 and 1/4
So, in conclusion, the answer to this question is: X = 3 and 1/4 as a mixed number or 13/4 as an improper fraction.
Glad I could help!


8 0
3 years ago
Find an equation for the line below.
vodka [1.7K]

Answer:

A(-6,-5) B(4,1)

Step-by-step explanation:

am not that sure

7 0
2 years ago
Read 2 more answers
If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f
Anni [7]

Answer:

Part A) Annual \$66,480.95  

Part B) Semiannual \$66,862.38  

Part C) Monthly \$67,195.44  

Part D) Daily \$67,261.54  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

so

Part A) Annual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=1  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{1})^{1*5}  

A=\$47,400(1.07)^{5}  

A=\$66,480.95  

Part B) Semiannual

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=2  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{2})^{2*5}  

A=\$47,400(1.035)^{10}  

A=\$66,862.38  

Part C) Monthly

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=12  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{12})^{12*5}  

A=\$47,400(1.0058)^{60}  

A=\$67,195.44  

Part D) Daily

in this problem we have  

t=5\ years\\ P=\$47,400\\ r=0.07\\n=365  

substitute in the formula above  

A=\$47,400(1+\frac{0.07}{365})^{365*5}  

A=\$47,400(1.0002)^{1,825}  

A=\$67,261.54  

8 0
3 years ago
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