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hichkok12 [17]
3 years ago
8

What is the least common multiple of the two denominators between 6/8 and 4/32

Mathematics
2 answers:
lukranit [14]3 years ago
8 0

Answer:

3/32 is the Least common multiple

Nostrana [21]3 years ago
3 0

Answer:4

Step-by-step explanation:

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Ari and Greg share a 12-ounce bucket of clay. By the end of the week, Ari has used 1 6 of the bucket, and Greg has used 2 3 of t
kotegsom [21]

Answer:

2 ounces of clay is left in the bucket

Step-by-step explanation:

Total amount of clay in the bucket = 12 ounce

Ari used 1/6th of the clay in the bucket and Greg used 2/3 of the clay in the bucket

Hence, the remaining clay in the bucket

12 - 1/6 *12 - 2/3 * 12

12 - 2-8

2

3 0
2 years ago
A system of equations is shown below:
padilas [110]

Answer:

y=3

x=2

Step-by-step explanation:

i have answered it....feel free to ask if u don't get it

8 0
3 years ago
How many squares make up the surface of a cube?<br>O A. Seven<br>O B. Five<br>O C. Six<br>D. Eight​
Blababa [14]
The answer to the question is C (6)
3 0
3 years ago
Read 2 more answers
Flying against the wind, a jet travels 2190 miles in 3 hours. Flying with the wind, the same jet travels 9520 miles in 8 hours.
dezoksy [38]

Answer:

Velocity of jet in still air is 970 miles per hour and velocity of wind is 210 miles per hour.

Step-by-step explanation:

Jet's velocity against wind is

3040/4 = 760 miles per hour and flying with wind it is

8260/7 = 1180 miles per hour.

Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.

As such its velocity against wind is x − y and with wind is x + y and therefore

x − y = 760 and x + y = 1180

Adding the two 2 x = 1940 and x = 970 and y = 1180 − 970 = 210

Hence velocity of jet in still air is 970 miles per hour and velocity of wind is

210 miles per hour.

Actual Answer:

https://socratic.org/questions/flying-against-the-wind-a-jet-travels-3040-miles-in-4-hours-flying-with-the-wind

7 0
3 years ago
1) Which of the following is a surd ? a) 64 b) 6 root 64 c) 4 root 64 d) 3 root 64
Mashcka [7]

Answer:

  \text{c) }\sqrt[4]{64}=2\sqrt[4]{4}

Step-by-step explanation:

\text{a) }64\qquad\text{an integer; not a surd}\\\\\text{b) }\sqrt[6]{64}=2\qquad\text{an integer; not a surd}\\\\\text{c) }\sqrt[4]{64}=2\sqrt[4]{4}\qquad\textbf{a surd}\\\\\text{d) }\sqrt[3]{64}=4\qquad\text{an integer; not a surd}

5 0
3 years ago
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