The bearing of the plane is approximately 178.037°. 
<h3>Procedure - Determination of the bearing of the plane</h3><h3 />
Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:
(1)
Where:
- Magnitude of the vector, in miles per hour.
- Direction of the vector, in degrees.
That is, the line of reference is the 
semiaxis.
The <em>resulting</em> vector (
), in miles per hour, is the sum of airspeed of the airplane (
), in miles per hour, and the speed of the wind (
), in miles per hour, that is:
(2)
If we know that 
, 
, 
and 
, then the resulting vector is:
![\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%287.986%2C%20-232.981%29%20%5C%2C%5Cleft%5B%5Cfrac%7Bmi%7D%7Bh%7D%20%5Cright%5D)
Now we determine the bearing of the plane (), in degrees, by the following <em>trigonometric</em> expression:
(3)
The bearing of the plane is approximately 178.037°.
To learn more on bearing, we kindly invite to check this verified question: brainly.com/question/10649078
Answer:
The 80,000
Step-by-step explanation:
The equation looks like this
y≤ -1/3x + 4
And it looks like
