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Trava [24]
4 years ago
10

An airplane is flying at 95.0 m/s when the engine is turned off. As it glides, it experiences a force of drag so that is slows d

own at -0.700 m/s2. How far in meters will it travel in 1.00 minute ?
Physics
1 answer:
kkurt [141]4 years ago
5 0
<h2>The airplane travels 4440 m in 1 minute</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 95 m/s

        Acceleration, a = -0.700 m/s²  

        Time, t = 1 minute = 60 seconds

     Substituting

                      s = ut + 0.5 at²

                      s = 95 x 60 + 0.5 x -0.700 x 60²

                      s = 4440 m

      Distance traveled is 4440 m

The airplane travels 4440 m in 1 minute

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Forces are measured in Newtons (N). Why are forces considered to be vectors?
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A catcher catches a 150g baseball traveling horizontally at 25 m/s. If the ball takes 20.ms to stop once it is in contact with t
rosijanka [135]

Answer:

The magnitude of the force exerted by the ball on the catcher is 1.9 × 10²  N

Explanation:

Hi there!

Let´s find the acceleration of the ball that makes it stop when caught by the catcher. The acceleration can be calculated from the equation of velocity considering that it is constant:

v = v0 + a · t

We know that initially the ball was traveling at 25 m/s, so, if we consider the position of the catcher as the origin of the frame of reference, then, v0 = -25 m/s. We also know that it takes the ball 20 ms (0.02 s) to stop (i.e. to reach a velocity of 0). Then using the equation of velocity:

v = v0 + a · t

0 m/s = -25 m/s + a · 0.020 s

25 m/s/ 0.020 s = a

Now, using the second law of Newton, we can calculate the force exerted by the catcher on the ball:

F = m · a

Where:

F = force.

m = mass of the ball.

a = acceleration.

F = 0.150 kg · (25 m/s/ 0.020 s) = 1.9 × 10²  N

According to Newton´s third law, the force exerted by the ball on the catcher will be of equal magnitude but opposite direction. Then, the force exerted by the ball on the catcher will have a magnitude of 1.9 × 10²  N.

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