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alekssr [168]
3 years ago
13

an airplane maintains a speed of 567 km/h relative to the air it is flying through as it makes a tripto a city 780 km away to th

e north a) what time interval is rquired for the trip if the plane flies through a headwind blowing at 33.0 km/h toawrd the south? b) what time interval is required if theres a tailwind with same speed? c) what time interval required if there is a crosswind blowing at 33 km/h to the east relative to the ground?
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0
A ) v = 567 - 33 = 534 km/h
     v = d / t    ⇒   t = d / v
     t = 780 km / 534 km/h = 1.46 h 
b ) v = 567 + 33 = 600 km/h
     t = 780 km / 600 km/h = 1.3 h
c ) v = (567² +33²) ^(1/2) = √320,400 = 566 km/h
     t = 780 km/ 566 km/h = 1.378 h
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Answer:Answer:

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8 0
3 years ago
(d)
deff fn [24]

Answer:

Frequency = 24 × 10⁸ Hz

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3 0
3 years ago
A friend of yours is loudly singing a single note at 412 Hz while racing toward you at 23.0 m/s on a day when the speed of sound
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f_0 = (\frac{v+v_0}{v-v_s})f_s

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PART A) Replacing our values we have that,

f_0 = (\frac{v+v_0}{v-v_s})f_s

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PART B) Here the same procedure is performed but this time repeated in the opposite direction.

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3 years ago
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