(a) What is
the potential energy: PE = -G * M * m/r
Where: M is the mass of the earth which is 5.98 * 10^24 kg.
m is the mass of the satellite.
r is the space from the center of the earth to the satellite
To conclude this distance add the radius of the earth to the
altitude. Radius of the earth is 6.38 * 10^6 meters.
r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6
PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 =
4.71240095 * 10^9 J
(b) magnitude of the gravitational force exerted by the
Earth
Fg = G * M * m/r^2
Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 =
562.3078873 N
(c) There are no other forces that the satellite exert on
the Earth. So therefore, it is 0.
Explanation:
20 meters is travelled by him
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Answer:
Explanation:
Total resistance of 2 bulb in series
= 100 +100 = 200 ohm
current in each bulb
= 9/200 = .045 A
In case of parallel combination of bulb
total resistance
= 100 x 100 / (100+100)
50 ohm
current in the main circuit
= 9 / 50 A
current in each bulb
= 9 / (2 x 50)
.09
So in the second case current is more , hence heat generated too will be more . So brightness too will be more.
First set ( in series ) will be dimmer.
Answer
given,
Q u = 8.7 m³/s
Q d= 0.9 m³/s
BOD concentration = 50 mg/L
a) BOD concentration at the down stream
= 4.69 mg/L
b) discharge = 9.6 m³/s
cross sectional area = 10 m²
velocity steam = 
= 0.96 m/s
time taken to move 50 km down stream =
= 52083.3 s
= 
= 0.6 days
now,
2.27 mps repeating.
This is the last question ill ever answer here. Thanks for being the last.
