Hi there!
At angle B, the light is refracted at an angle in one direction as it enters the glass. As it exits the glass at angle C, It is refracted at another angle in the opposite direction.
Hope this helps, have a nice day :)
(a) 0.0068 Wb
Since the plane of the coil is perpendicular to the magnetic field, the magnetic flux through the coil is given by

where
N = 200 is the number of loops in the coil
B is the magnetic field intensity
is the area of the coil
At the beginning, we have

so the initial magnetic flux is

at the end, we have

so the final magnetic flux is

So the magnitude of the change in the external magnetic flux through the coil is

(b) 0.567 V
The magnitude of the average voltage (emf) induced in the coil is given by Faraday-Newmann law

where
is the variation of magnetic flux
is the time interval
Substituting into the formula, we find

(c) 0.142 A
The average current in the coil can be found by using Ohm's law:

where
I is the current
V is the voltage
R is the resistance
Here we have:
V = 0.567 V (induced voltage)
(resistance of the coil)
Solving for I, we find

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Answer:
The power she can generate is 185.22 KW.
Explanation:
<h3><u>DATA</u></h3>
3.00m wide and 0.500m deep.
Cross sectional area = 1.500m^2
Velocity = 1.35m/s
Volumetric flow rate = Av = 18.00m^3/s
Mass flow rate = 18,000kg/s
Height = 4.20m
25.0% efficiency
<h3><u>
FORMULA:</u></h3>
P = dE / dt * eff
<h3><u>
SOLUTION:</u></h3>
18,000kg/s (9.8m/s^2) (4.20m) (25%) = 185,220 watts
= 185 kw