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marshall27 [118]
3 years ago
14

Common Factors for 21 and 63

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

I think it is this but I haven't done factors in a long time

for 21:

1, 3, 7 and 21

for 63

(1, 63), (3, 21) and (7, 9).

hope this helps!

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DerKrebs [107]

Answer:

  • Area of the circle is 56.25π square feet.

Step-by-step explanation:

<u>Given that</u>:

  • The circumference of a circle is 15π ft.

<u>To Find</u>:

  • What is the area, in square feet?

<u>We know that</u>:

  • Circumference of a circle = 2πR
  • Area of a circle = πR²

Where,

  • Radius is denoted as R.

<u>Finding the radius of the circle</u>:

Circumference of a circle = 15π

⟶ 2πR = 15π

⟶ 2πR = 2π × 7.5

Cancelling 2π.

⟶ R = 7.5

∴ Radius of the circle = 7.5 ft.

<u>Finding the area of the circle</u>:

⟶ Area = πR²

⟶ Area = π(7.5)²

⟶ Area = π × 7.5 × 7.5

⟶ Area = π × 56.25

⟶ Area = 56.25π

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7 0
4 years ago
Line segment TV is a midsegment of ∆QRS. What is the value of n in the triangle pictured?
Elis [28]

Answer:

D. 3.2

Step-by-step explanation:

Mid-segment Theorem of a triangle states that the Mid-segment in a triangle is half of the third side of the triangle.

Based on this theorem, we have: TV = ½(RS)

TV = 3n - 2

RS = n + 12

Substitute

3n - 2 = ½(n + 12)

Multiply both sides by 2

2(3n - 2) = (n + 12)

6n - 4 = n + 12

Collect like terms

6n - n = 4 + 12

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5n/5 = 16/5

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Step-by-step explanation:

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A large university accepts 70% of the students who apply. Of the students the university accepts, 25% actually enroll. If 20,00
Komok [63]

Answer:

3500

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