Answer: The empirical formula for C6H12O6 is CH2O. Every carbohydrate, be it simple or complex, has an empirical formula CH2O
Explanation:
It's your hw so you really should understand it so you dont have to ask for help so I'll try to explain it the best I can.
1.SD (only one switch occurs, between fluorine and bromide)
2.DD (two things are switched, sulfate and nitrate)
3. D (One compound is broken up into smaller compounds)
4.C (The products of combustion are always h20 and co2)
5.DD (again, two things are switched, bromide and nitrate)
6.SD (In SDR, look for a lone molecule reacting with a compound)
7.S (two smaller compounds become one big compound)
8. D( A big compound is broken up)
9. DD (I think Its DD because two molecules were displaced)*not sure
10.DD(two molecules are displaced, phosphate and hydroxide)
CCl4 is the answer to This
Explanation:
Bromine is a chemical element with the symbol Br and atomic number 35. It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly coloured vapour. Its properties are intermediate between those of chlorine and iodine. Isolated independently by two chemists, Carl Jacob Löwig (in 1825) and Antoine Jérôme Balard (in 1826), its name was derived from the Ancient Greek βρῶμος ("stench"), referring to its sharp and disagreeable smell.
Bromine, 35Br
Answer:
CN⁻(aq) + H⁺(aq) ⇒ HCN(aq)
Explanation:
Let's consider the following molecular equation.
NaCN(aq) + HI(aq) ⇒ NaI(aq) + HCN(aq)
HI is a strong electrolyte so it exists mostly in the ionic form. HCN is a weak electrolyte so it exists mostly in the molecular form.
The full ionic equation includes all the ions and the molecular species.
Na⁺(aq) + CN⁻(aq) + H⁺(aq) + I⁻(aq) ⇒ Na⁺(aq) + I⁻(aq) + HCN(aq)
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
CN⁻(aq) + H⁺(aq) ⇒ HCN(aq)