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Kitty [74]
3 years ago
15

Identity the transformation that was applied to this letter.​

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0

Answer:

Rotation around the origin.

The image was rotated 90 degrees clockwise

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Let f(x) = 1/x+2 and g (x) = 1/x-3. Find (f/g) (x). Assume all appropriate restrictions to the domain. help!!!!
DanielleElmas [232]

Answer:(f/g)(x)=(1+2x)/(1-3x) where x<>0

Step-by-step explanation:

f(x)= 1/x+2= (1+2x)/x  ,   x<>0

g(x)=1/x-3=(1-3x)/x    , x<>0

=>f(x)/g(x)= (1+2x)/(1-3x)    ,  x<>0

3 0
3 years ago
I need help with this problem
castortr0y [4]

Answer:

c. 106 million

Step-by-step explanation:

A = number of people in the sample that use public transportation 5 or more days per week

A = 2,067,153

B = number of people total in the sample

B = 4,295,280

C = proportion of those in the sample that use public transportation 5 or more days per week

C = A/B

C = (2,067,153)/(4,295,280)

C = 0.48126 approximately

Multiply this value by the figure 220 million to compute the estimated number of people who use public transportation 5 or more days per week

C*(220 million) = 0.48126*(220 million) = (0.48126*220) million = 105.8772 million = 106 million

6 0
3 years ago
Powers of 10 and Exponents (number 4 is a 10 incase u can’t see of the ripped page.)
vodomira [7]

Answer:

below

Step-by-step explanation:

2) 10², the second power of ten

3) 10⁴, the fourth power of ten

4) 1000

5) 400

6) 90,000

7) 10

8) 100,000

9) 50

10) 7000

11) 8

12) 24 x 10⁴

13) 93,000,000

4 0
1 year ago
Read 2 more answers
In a shipment of 22 smartphones, 2 are defective. How many ways can a quality control inspector randomly test 4 smartphones, of
Eddi Din [679]

Answer:

Therefore the required ways are =190

Step-by-step explanation:

Combination: Combination is the number of selection of items from a collection of items where the order of selection does not matter.

Total number of smartphones =22

Defective phone = 2

Non defective phone = (22-2) =20

The control inspector randomly test 4 smartphones of which 2 are defective.

Non defective phone = 2

The ways to select 2 non defective phone is

^{20}C_2=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!}=\frac{19\times 20}{2} =190

The ways to select 2 defective phone is= ^2C_2=1

Therefore the required ways are = (190×1) =190

5 0
3 years ago
4j + 4j − 6j − j = 12 <br> Solve for J
kherson [118]
J equals 12...........
3 0
3 years ago
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