Answer:
y - 3 = (2/5)(x + 2)
Step-by-step explanation:
Start with the general point-slope form of the equation of a straight line:
y - k = m(x - h). Now substitute -2 for h and 3 for k, and also 2/5 for m:
y - 3 = (2/5)(x + 2)
(i just changed my answer)
sqrt is the square root of
v=sqrt(2(ke)/m)
If I were you, I would make the starting point (3,-6). From there, you will want to use the slope of -1/2 (go down 1 unit and to the right 2 units and draw a point)
Do you want 5 and 6 or just 5? 5 is kind of neat.
44.5% = 0.445
4/9 = 0.4444444
You have enough information to put the numbers in order.
0.44 is the smallest number.
0.44444444.... is the next smallest number
0.4445 is bigger than the number above. 5 is in the ten thousandths place. that is bigger than 4 in the thousands place of 4/9
Finally the largest number of all is 0.445 for the same reason given above.
Six
5/12 = 0.416666
0.4
42% = 42/100 = 0.42
0.416
0.4 is the smallest number
0.416 is the next smallest number
0.41666666 is bigger than 0.416 because you are adding a bunch of 6s onto the decimal place.
The largest one is 0.42. You can put these into your calculator to verify the results. For example, 0.42 - 0.4166666 = 0.003344. Any result more than 0 will show that the first number is bigger than the second.
Answer:
Problem 23) 
Problem 24) 
Step-by-step explanation:
step 1
Find the slope of the given line
The formula to calculate the slope between two points is equal to

we have

Substitute the values


step 2
Problem 23
we know that
If two lines are perpendicular then the product of its slopes is equal to minus 1
so

Find the slope of the line
we have

substitute in the equation and solve for m2


with the slope m2 and the point
find the equation of the line
Remember that
The equation of the line in slope intercept form is equal to

we have

-----> the given point is the y-intercept
substitute

step 3
Problem 24
we know that
If two lines are parallel, then its slopes are the same
so
with the slope m1 and the point
find the equation of the line
The equation of the line in slope intercept form is equal to

we have

-----> the given point is the y-intercept
substitute
