To find t<span>he relative maximum value of the function we need to find where the function has its first derivative equal to 0.
Its first derivative is -7*(2x)/(x^2+5)^2
</span>7*(2x)/(x^2+5)^2 =0 the numerator needs to be eqaul to 0
2x=0
x=0
g(0) = 7/5
The <span>relative maximum value is at the point (0, 7/5).</span>
Answer:
(X=Y)=(3,6)
Step-by-step explanation:
5x-4(4x-6)=-9
x=3
y=4x3-6
y=6
Answer:
x(t) = –5 + 6t; y(t) = 3 – 9t
Step-by-step explanation:
Extraneous root since dividing by zero is undefined
