1.4 as a mixed number would look like this:
or 1 2/5
Hope this helps you
-AaronWiseIsBae
<span>(u + 7) + 13 = u + (7 + 13)
The associative property of addition says that you can add numbers regardless of how they're grouped and get the same result. So let's look at the options and see what makes sense.
(u + 7) + 13 = u + (7 + 13)
* This is showing the associative property like the definition states. So this is the correct choice.
21 + 2y = 2y + 21
* This is a demonstration of the commutative property of addition. So it's the wrong choice for this question.
3â‹…(5â‹…x)=(3â‹…5)â‹…x
* This is showing the associative property of multiplication. So it's the wrong choice for this question.
If m + 3 = 18, then 18 = m + 3.
* This is a demonstration of the symmetric property of equality. So for this question, it's the wrong choice.</span>
Answer:
Option C
Step-by-step explanation: I think this is right because when you substitute the 2 for x you get the answer. Hope this helps darling!!
Answer with Step-by-step explanation:
We know that the components of velocity are obtained from position as
![u=\frac{dx}{dt}\\\\v=\frac{dy}{dt}](https://tex.z-dn.net/?f=u%3D%5Cfrac%7Bdx%7D%7Bdt%7D%5C%5C%5C%5Cv%3D%5Cfrac%7Bdy%7D%7Bdt%7D)
Using the given values we obtain
![u=\frac{d(2t^2)}{dt}\\\\u=4t](https://tex.z-dn.net/?f=u%3D%5Cfrac%7Bd%282t%5E2%29%7D%7Bdt%7D%5C%5C%5C%5Cu%3D4t)
Similarly
![v=\frac{d(t^2-41)}{dt}\\\\u=2t](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%28t%5E2-41%29%7D%7Bdt%7D%5C%5C%5C%5Cu%3D2t)
The the velocity function can be written as
![\overrightarrow{v}=4t\widehat{i}+2t\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D%3D4t%5Cwidehat%7Bi%7D%2B2t%5Cwidehat%7Bj%7D)
The components of acceleration are obatined from the components of velocity as
![a_{x}=\frac{du}{dt}\\\\a_{y}=\frac{dv}{dt}](https://tex.z-dn.net/?f=a_%7Bx%7D%3D%5Cfrac%7Bdu%7D%7Bdt%7D%5C%5C%5C%5Ca_%7By%7D%3D%5Cfrac%7Bdv%7D%7Bdt%7D)
Using the given values we obtain
![a_x=\frac{d(4t)}{dt}\\\\a_{x}=4](https://tex.z-dn.net/?f=a_x%3D%5Cfrac%7Bd%284t%29%7D%7Bdt%7D%5C%5C%5C%5Ca_%7Bx%7D%3D4)
Similarly
![a_y=\frac{d(2t)}{dt}\\\\a_y=2](https://tex.z-dn.net/?f=a_y%3D%5Cfrac%7Bd%282t%29%7D%7Bdt%7D%5C%5C%5C%5Ca_y%3D2)
The the acceleration function can be written as
![\overrightarrow{a}=4\widehat{i}+2\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Ba%7D%3D4%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D)
Thus at time 't=1' the velocity function becomes
![\overrightarrow{v}=4\widehat{i}+2\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D%3D4%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D)
Thus the component of acceleration in the direction of the given vector
can be found by taking the dot product of the 2 vectors
Thus we get
![v_{r}=\overrightarrow{v}\cdot \overrightarrow{r}\\\\v_{r}=(4\widehat{i}+2\widehat{j})\cdot (\widehat{i}-3\widehat{j})\\\\v_{r}=4-6=-2](https://tex.z-dn.net/?f=v_%7Br%7D%3D%5Coverrightarrow%7Bv%7D%5Ccdot%20%5Coverrightarrow%7Br%7D%5C%5C%5C%5Cv_%7Br%7D%3D%284%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D%29%5Ccdot%20%28%5Cwidehat%7Bi%7D-3%5Cwidehat%7Bj%7D%29%5C%5C%5C%5Cv_%7Br%7D%3D4-6%3D-2)
Similarly the dot product is obtained for acceleration as
![a_{r}=\overrightarrow{a}\cdot \overrightarrow{r}\\\\a_{r}=(4\widehat{i}+2\widehat{j})\cdot (\widehat{i}-3\widehat{j})\\\\a_{r}=4-6=-2](https://tex.z-dn.net/?f=a_%7Br%7D%3D%5Coverrightarrow%7Ba%7D%5Ccdot%20%5Coverrightarrow%7Br%7D%5C%5C%5C%5Ca_%7Br%7D%3D%284%5Cwidehat%7Bi%7D%2B2%5Cwidehat%7Bj%7D%29%5Ccdot%20%28%5Cwidehat%7Bi%7D-3%5Cwidehat%7Bj%7D%29%5C%5C%5C%5Ca_%7Br%7D%3D4-6%3D-2)
Answer: 0.05%
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Work Shown:
To go from percent form to decimal form, move the decimal over 2 spots to the left. Think of 2% as 2.0%
2% = 0.02
2.5% = 0.025
Multiply the decimal form of each percentage
0.02*0.025 = 0.0005
Convert that result to a percentage. Move the decimal 2 spots to the right
0.0005 = 0.05% is the probability both break down
Note: This multiplication rule only works if the two events are independent.