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BabaBlast [244]

2 years ago

11

Commemorative coins come in packs of 15, while coin holders come in packs of 25. What are the least numbers of packs you shoul

d buy in order to have the same numbers of coins and coin holders?

1 answer:

Elis [28]2 years ago

5 0

Answer:

5 Commemorative coin packs

3 coin holders

Step-by-step explanation:

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What is the average of 1.90 7.99 4.33 5.21?

nadezda [96]

Add All The Numbers (Which Gives You 19.43) Then Divide By Four Because There Are Four Numbers That Were Added Together. The Average Is 4.8575.

7 0

3 years ago

Read 2 more answers

What is the most accurate representation of the area of a plot measuring 11.7 cm by 15.4 cm?

sergiy2304 [10]

In the given question the length and width of the plot are already given. although there is no direct specification regarding the one that is length or the one that is the width, so it can be taken as your own choice. This will not affect the ultimate answer.
So
Area of the rectangular plot = Length * Width
= 11.7 * 15.4 square cm
= 180.18 square cm
So the area of the rectangular plot as can be seen from the above deduction is 180.18 square centimeter.

6 0

3 years ago

A house was valued at $238,000. Over several years, the value decreased by 16%, giving the house a new value.

Neko [114]

Answer:

The new value of the house after the 16% decrease would be $199,920.

Step-by-step explanation:

Given that a house was valued at $ 238,000, and over several years, the value decreased by 16%, giving the house a new value, to determine the new value the following calculation must be performed:

238,000 - (238,000 x 0.16) = X

238,000 - 38,080 = X

199.920 = X

Thus, the new value of the house after the 16% decrease would be $ 199,920.

8 0

2 years ago

Help me to solve this question

Lynna [10]

Answer:

$\left \{ {{\theta_1=\frac{\pi }{4} } \atop {\theta_2=\frac{3\pi }{4} }} \right. .$

Step-by-step explanation:

$2*cos^2\theta-1=0\ \ \ \ (0^0\leq \theta\leq 360^0)\ \ \ \ \ \theta=?\\2*cos^2\theta-(sin^2\theta+cos^2\theta)=0\\2*cos^2\theta-sin^2\theta-cos^2\theta=0\\cos^2\theta-sin^2\theta=0\\cos2\theta=0\\0^0\leq \theta\leq 360^0\ \ \ \ \Rightarrow\\\left \{ {{2\theta=\frac{\pi }{2}\ |:2 } \atop {2\theta=\frac{3\pi }{2}\ |:2 }} \right. \ \ \ \ \left \{ {{\theta_1=\frac{\pi }{4} } \atop {\theta_2=\frac{3\pi }{4} }} \right. .$

Good luck and have a nice day!

7 0

2 years ago

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is

anastassius [24]

Answer:

The rate of change of temperature is 1.29 degree Celsius per second.

Step-by-step explanation:

We are given the following information in the question:

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius where x and y are measured in centimeters.

$x = \sqrt{2+t}\\\\y = 5 + \displaystyle\frac{1}{14}t$

$T_x(4,6) = 8, T_y(4,6) = 4$

We have to find the rate at which the temperature is rising on the bug's path after 14 seconds.

At t = 14 seconds, we have,

$x = \sqrt{2+14} = 4\\\\y = 5 + \displaystyle\frac{1}{14}(14) = 5+1 = 6$

To find rate of change of temperature, we differentiate,

$\displaystyle\frac{dT}{dt} = \frac{dT}{dx}\frac{dx}{dt} + \frac{dT}{dy}\frac{dy}{dt}\\\\\displaystyle\frac{dT}{dt} = T_x(x,y)(\frac{1}{2\sqrt{2+t}}) + T_y(x,y)\frac{1}{14}\\\\At~ t = 14, x = 4, y = 6\\\\\frac{dT}{dt} = T_x(4,6)(\frac{1}{2\sqrt{2+t}}) + T_y(4,6)\frac{1}{14}\\\\\frac{dT}{dt} = 8\times \frac{1}{8} +4\times \frac{1}{14} = 1 + 0.2857 = 1.2857$

Thus, the rate of change of temperature is 1.29 degree Celsius per second.

7 0

3 years ago