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Svetach [21]
3 years ago
12

The second side of a triangular deck is 5 feet longer than the shortest​ side, and the third side is 5 feet shorter than twice t

he length of the shortest side. If the perimeter of the deck is 72 ​feet, what are the lengths of the three​ sides?
Mathematics
1 answer:
viva [34]3 years ago
5 0

Answer: the length if the three sides are 31 feet, 23 feet and 18 feet.

Step-by-step explanation:

Let x represent the length of the shortest side of the triangle.

Let y represent the length of the second side of the triangle.

Let z represent the length of the third side of the triangle.

The second side of a triangular deck is 5 feet longer than the shortest​ side. This means that

y = x + 5

The third side is 5 feet shorter than twice the length of the shortest side. This means that

z = 2x - 5

If the perimeter of the deck is 72 ​feet, it means that

x + x + 5 + 2x - 5 = 72

4x = 72

x = 72/4 = 18

z = 2x - 5 = 2 × 18 - 5

z = 36 - 5

z = 31

y = x + 5 = 18 + 5

y = 23

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I need help!!! Pleasssse!!!!
Zinaida [17]
Given the ratio, you know that:
length = 6x
width = 2x
height = 7x

Because the sum of the length and the width is 24 cm, you can write the equation:
6x + 2x = 24
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Plug the 3 back into the expressions written earlier for length, width, and height.
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width = 6 cm
height = 21 cm

Use the formula SA = 2B + Ph to solve for the surface area.
Surface Area = 2(area of the base) + (perimeter of the base)(height)

I'm going to plug in l, w, and h as variables for length, width, and height to show the exact way to solve for the B and P.
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