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horsena [70]
3 years ago
13

Can someone plz help me with this one problem plz

Mathematics
2 answers:
zalisa [80]3 years ago
4 0
8mm because area=length X width and 8x4 would be equal to 32mm
ICE Princess25 [194]3 years ago
3 0
8mm bc a=lw. If a=32 and l=4, you get 4w=32. Then, solve for w.
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A student bikes 1/4 mile to school. After school, the student bikes 1/3 mile to a cousin’s house. Finally, the student bikes 7/1
gizmo_the_mogwai [7]

The miles the student biked in two weeks is 11 2/3 miles.

The distance the student bikes is given in fractions. Fractions are numbers that are made up of numerator and denominators. An examples of a fraction is 1/4. 1 is the numerator and 4 is the denominator.

In order to determine the distance biked in 2 weeks, the distance biked in a day has to be determined.

Distance biked in a day =  (1/4 + 1/3 + 7/12)

14/12 = 1 2/12 = 1 1/6

Distance he would travel in 2 weeks

1 1/6 x 10

7/6 x 10 = 70 /6 = 11 2/3 miles

To learn more about fractions, please check: brainly.com/question/848992

5 0
3 years ago
Find the commission on a sale of $600 with a 5% commission rate.
lana [24]

Answer:

30

Step-by-step explanation:

5% of 600 is 30 so that should be ur answer

8 0
2 years ago
Three friends go grocery shopping together, and each buys the same kind of
dalvyx [7]

Answer:

C

Step-by-step explanation:

Because if you plug those numbers into the graph, only C and D fit. Now we have to look at the unit price. If LaMar buys 2 lbs and pays 3.00 dollars, we know that the unit price is 3/2=1.5 dollars per pound. You could also check with the other peoples. $7.5/5lbs=1.5 dollars. $4.5/3lbs=$1.5

3 0
3 years ago
Mandy created a treasure hunt in the sand at the beach. To keep track of where she buried four items, she graphed their location
rjkz [21]
I need a picture plzzzzz
5 0
3 years ago
Find the length of the altitude drawn to the hypotenuse. The triangle is not drawn to scale.
Serga [27]
We can solve this by understanding triangle rules and seeing the two right triangles that together form the whole right triangle. Lastly we'll use some basic Trig.
Let's start by labeling the triangles:
Let's make the bottom left angle (next to 5) "b"
Then we'll call the small angle at the top, which is the apex of the small triangle, "a". The height of the triangles we'll call "x".
So for the angles at this point, if a + b (as we've called them) are the other 2 angles of a right triangle, then a + b = 90.
Why? because all (3) angles of any triangle always sum (add up) to the 180.
if a + b = 90, then a = 90-b
Now let's look at the triangle on the right: it has 90 as it's left angle, and b as apex (top) angle, the angle on the right must add to b to make 90, so it's 90-b
plug "a" in for "90-b" --> now we have an a, b, and 90 for the small right and for the small left triangle.
For the left triangle: take the tangent (tan) of angle a, which = the opposite side (O) ÷ adjacent side (A) --> tan(a) = O/A = 5/x
For the other triangle: tangent of that angle a = O/A --> tan(a) =x/26
Now if tan(a) = 5/x AND tan(a) = x/26, we can plug one into the other:
tan(a) = x/26
5/x = x/26
cross-multiply
x * x = 5 * 26
{x}^{2}  = 130 \\  \sqrt{ {x}^{2} }  =  \sqrt{130}  \\ x =  \sqrt{130}
5 0
3 years ago
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