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Ann [662]
3 years ago
9

A pet store has three fish tanks, each holding a different volume of water and a different number of fish. Tank AAA holds 40\tex

t{ L}40 L40, start text, space, L, end text and 555 fish. Tank BBB holds 100\text{ L}100 L100, start text, space, L, end text and 121212 fish. Tank CCC holds 180\text{ L}180 L180, start text, space, L, end text and 232323 fish.
Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

The tanks by volume per fish from least to greatest:

Tank C, Tank A, Tank B

Step-by-step explanation:

A pet store has three fish tanks, each holding a different volume of water and a different number of fish.

Order the tanks by volume per fish from least to greatest.

Tank A holds 40 L and 5 fish.

= 40L/5 fishes

= 8 volume per fish

Tank B holds 100 L and 12 fish

= 100L/12 fishes

= 8.3333333333 volume per fish

Tank C holds 180 L and 23 fish.

= 180L /23 fish

= 7.8260869565 volume per fish

The tanks by volume per fish from least to greatest

Tank C, Tank A, Tank B

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stellarik [79]

Answer:

42

Step-by-step explanation:

42-6 = 36

36*2 = 72

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2 years ago
3-2i/5+i<br><img src="https://tex.z-dn.net/?f=3%20-%202i%20%5Cdiv%205%20%20%2B%20i%20%20" id="TexFormula1" title="3 - 2i \div 5
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3-2i/5+i

\frac{3*5+(-2)*1)+(-2*5-3*1)i}{5^2+1^2}

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Hope this helps!

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3 years ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

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