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Ann [662]
3 years ago
9

A pet store has three fish tanks, each holding a different volume of water and a different number of fish. Tank AAA holds 40\tex

t{ L}40 L40, start text, space, L, end text and 555 fish. Tank BBB holds 100\text{ L}100 L100, start text, space, L, end text and 121212 fish. Tank CCC holds 180\text{ L}180 L180, start text, space, L, end text and 232323 fish.
Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

The tanks by volume per fish from least to greatest:

Tank C, Tank A, Tank B

Step-by-step explanation:

A pet store has three fish tanks, each holding a different volume of water and a different number of fish.

Order the tanks by volume per fish from least to greatest.

Tank A holds 40 L and 5 fish.

= 40L/5 fishes

= 8 volume per fish

Tank B holds 100 L and 12 fish

= 100L/12 fishes

= 8.3333333333 volume per fish

Tank C holds 180 L and 23 fish.

= 180L /23 fish

= 7.8260869565 volume per fish

The tanks by volume per fish from least to greatest

Tank C, Tank A, Tank B

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Answer:

Options 1, 3 and 4 are true

Step-by-step explanation:

The legs EF and DF of the right triangle DEF have lengths of 24 units and 7 units, respectively. By the Pythagorean theorem,

DE^2=EF^2+DF^2\\ \\DE^2=24^2+7^2\\ \\DE^2=576+49\\ \\DE^2=625\\ \\DE=25\ units

Find trigonometric functions:

\sin \angle D=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}

\cos \angle E=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{EF}{DE}=\dfrac{24}{25}

\tan \angle D=\dfrac{\text{Opposite leg}}{\text{Adjacent leg}}=\dfrac{EF}{DF}=\dfrac{24}{7}

\sin \angle E=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{DF}{DE}=\dfrac{7}{25}

Thus, options 1, 3 and 4 are true

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