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3 years ago

Plzzzzzzzzzzzzzz help

Mathematics

1 answer:

givi [52]3 years ago

8 0

Answer:

1.05114

Step-by-step explanation:

that is the correct answer

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What is an equation of the line that passes through the points (0,-2) and (-5,4)

faust18 [17]

Answer: y = -6/5x - 2

Step-by-step explanation:

Slope = Change in y/Change in x

Our y intercept is -2 because of our point (0,-2)

5 0

3 years ago

An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 3500 feet and Plane B is at an altitude

MrRa [10]

3500 + 40.25s = 2768 + 55.5s
3500 - 2768 = 55.5s - 40.25s
732 = 15.25s
732 / 15.25 = s
48 = s......same at 48 seconds

3500 + 40.25(48)
3500 + 1932
5432 <== altitude

7 0

3 years ago

Find the value of y for which line a is parallel to line b.

alexdok [17]

Y+38°= 180 beacuse if a and b are parallel they are co interior angles. This means that they will at to 180.

y=180-38= 142°

Answer: 142°

Drew out some hopefully helpful pictures below. Hope they help! let me know if you still have any questions!

6 0

3 years ago

Classify What type of number is the square root of 2

Amanda [17]

Answer:

The square root of 2, or the (1/2)th power of 2, written in mathematics as √2 or 21⁄2, is the positive algebraic number that, when multiplied by itself, equals the number 2. Technically, it is called the principal square root of 2, to distinguish it from the negative number with the same property

Step-by-step explanation:

8 0

4 years ago

Problem Page

MrMuchimi

Answer:

1 machine must be made to minimise the unit cost.

Step-by-step explanation:

Step 1: Identify the function

x is the number of machines

C(x) is the function for unit cost

C (x) = 0.5x^2-150 + 21,035

Step 2: Substitute values in x to find the unit cost

C (x) = 0.5x^2-150 + 21,035

The lowest value of x could be 1

To check the lowest cost, substitute x=1 and x=2 in the equation.

When x=1

C (x) = 0.5x^2-150 + 21,035

C (x) = 0.5(1)^2-150 + 21,035

C (x) = 20885.5

When x=2

C (x) = 0.5x^2-150 + 21,035

C (x) = 0.5(2)^2-150 + 21,035

C (x) = 20887

We can see that when the value of x i.e. the number of machines increases, per unit cost increases.

Therefore, 1 machine must be made to minimise the unit cost.

3 0

3 years ago

Plzzzzzzzzzzzzzz help​

Plzzzzzzzzzzzzzz help