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Tanzania [10]
3 years ago
8

(A) In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a

further step to isolate it. Let's say we now have:
3C+4D=5
2C+5D=2
None of these terms has a coefficient of 1. Instead, we'll pick the variable with the smallest coefficient and isolate it. Move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient.
(B) Now that you have one of the two variables in Part (A) isolated, use substitution to solve for the two variables. You may want to review the Multiplication and Division of Fractions and Simplifying an Expression Primers..
Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

C = 17/7 or 2 3/7

D = -4/7

Step-by-step explanation:

3C+4D=5

2C+5D=2

2C = 2 - 5D

C = 1 - 2.5D

3(1 - 2.5D) + 4D = 5

3 - 7.5D + 4D = 5

-3.5D = 2

D = -4/7

C = 1 - 2.5(-4/7)

C = 1 + 10/7 = 17/7

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How do you solve interquartile range?
77julia77 [94]
By Hand
Step 1: 
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2: 
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3: 
Place parentheses around the numbers above and below the median. 
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4: 
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7),  9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.

Step 5: 
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
5 0
3 years ago
Read 2 more answers
Billy did a survey to answer the following question:
kogti [31]

Answer:

7.8

Step-by-step explanation:

Since the average is 7.8 and everyone scored the same score so

that means everyone scored a 7.8

4 0
3 years ago
Find the values ofx and y for the triange.<br> x<br> 60°<br> 30°<br> у
egoroff_w [7]

Answer:

x = 42, y = 36.37

Step-by-step explanation:

6 0
3 years ago
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The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
Estimate the isoelectric point of a ser–his dipeptide. explain why this value is only an estimate.
uranmaximum [27]
A dipeptide bond connects two amino acids. Ser stands for Serine while His stands for Histidine. Isoelectric point is when all charges of the two amino acids cancel out. This can be estimated by finding the average of the isoelectric points (pI) of the two amino acids.

Serine: pI = 5.68
Histidine: pI = 7.59

Average pI = (5.68 + 7.59)/2 =<em> 6.635

</em>
<em />This is only a rough estimate because an arithmetic average will not coincide with the biochemistry of the amino acids. The true value of the isolectric point is determined through experimentation. However, it would be more ore less around 6.635.<em>
</em>
3 0
3 years ago
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