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satela [25.4K]
3 years ago
10

The Royals softball team

Mathematics
2 answers:
Julli [10]3 years ago
8 0

Answer:

73%

Step-by-step explanation:

55/75 = .733333333

So the answer is 73%, rounded.

Hope this helps

hram777 [196]3 years ago
6 0
Answer:73% or 73.33repeating
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Which number can each term of the equation be multiplied by to eliminate the fractions before solving ? -3/4 m-1/2=2+1/4mA 2B 3C
bixtya [17]

The correct answer is C. 4.

Typically, we look to multiply by the bottom number (the denominator) in order to get fractions to cancel out. If we multiply 1/6 by 6, we get just 1, which is why we do it.

In this problem, you have two different denominators, 2 and 4. If you multiply them all by 2, the term -3/4m will still be a fraction.

-3/4m * 2 = -3/2m

As a result, we must try 4 instead. This causes all of them to cease being a fraction. Even the one with 2 as a denominator.

-1/2 * 4 = -2

7 0
3 years ago
Read 2 more answers
Solve this equation 3/8n=-1/4
lianna [129]
(3/8)*n = -1/4 // + -1/4

(3/8)*n-(-1/4) = 0

(3/8)*n+1/4 = 0

3/8*n+1/4 = 0 // - 1/4

3/8*n = -1/4 // : 3/8

n = -1/4/3/8

n = -2/3

n = -2/3
6 0
3 years ago
1. The side view of Mrs. Marigold's roof on her house
Ostrovityanka [42]

Answer:

The height of Mrs. Marigold's roof is 10 feet.

Step-by-step explanation:

Given that,

Base of the given triangle = 48 ft

Hypotenuse = 26 ft

Half of the base = 24 ft

Using Pythagoras theorem,

h=\sqrt{26^2-24^2}\\\\h=10\ ft

So, the height of Mrs. Marigold's roof is 10 feet.

7 0
3 years ago
Prove that if $w,z$ are complex numbers such that $|w|=|z|=1$ and $wz\ne -1$, then $\frac{w+z}{1+wz}$ is a real number.
mr_godi [17]

Answer:

See proof below

Step-by-step explanation:

Let r=\frac{w+z}{1+wz}. If w=-z, then r=0 and r is real. Suppose that w≠-z, that is, r≠0.

Remember this useful identity: if x is a complex number then x\bar{x}=|x|^2 where \bar{x} is the conjugate of x.

Now, using the properties of the conjugate (the conjugate of the sum(product) of two numbers is the sum(product) of the conjugates):

\frac{r}{\bar{r}}=\frac{w+z}{1+wz} \left(\frac{1+\bar{w}\bar{z}}{\bar{w}+\bar{z}}{\right)

=\frac{(w+z)(1+\bar{w}\bar{z})}{(1+wz)(\bar{w}+\bar{z})}=\frac{w+z+w\bar{w}\bar{z}+z\bar{z}\bar{w}}{\bar{w}+\bar{z}+\bar{w}wz+\bar{z}zw}=\frac{w+z+w+|w|^2\bar{z}+|z|^2\bar{w}}{\bar{w}+\bar{z}+|w|^2z+|z|^2w}=\frac{w+z+\bar{z}+\bar{w}}{\bar{w}+\bar{z}+z+w}=1

Thus \frac{r}{\bar{r}}=1. From this, r=\bar{r}. A complex number is real if and only if it is equal to its conjugate, therefore r is real.

3 0
3 years ago
Can you please help me ​
finlep [7]

Answer:

x=10

Step-by-step explanation:

8x+10=6x+30

8x-6x=30-10

2x=20

x=10

3 0
4 years ago
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