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n200080 [17]
3 years ago
13

The length of a rectangle is 5.5 feet. If the area is 44 square feet, what is the width of the rectangle, in feet?

Mathematics
2 answers:
vlabodo [156]3 years ago
7 0
So area is length times width therefore
A=LW
44ft^2=5.5W
divide both sides by 5.5
44/5.5=Width=8 feet
Flauer [41]3 years ago
5 0
When finding area of a rectangle, you multiply width x length.
width x length = area
Width x 5.5 = 44
Divide both sides by 5.5
Width =8
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3 years ago
11. In AWTY, if mZW is five less than twice mZY and mZX is 21 more than m_Y find the measure
wolverine [178]

9514 1404 393

Answer:

  angles (W, X, Y) = (77°, 62°, 41°)

Step-by-step explanation:

<u>Given</u>:

  ΔWZY

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  ∠X = ∠Y +21°

<u>Find</u>:

  ∠X, ∠Y, ∠W

<u>Solution</u>:

Using angle measures in degrees, we have ...

  ∠X + ∠Y + ∠Z = 180

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  4(∠Y) +16 = 180 . . . . . simplify

  ∠Y +4 = 45 . . . . . . . . . divide by 4

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The angle measures of angles (W, X, Y) are (77°, 62°, 41°), respectively.

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2 years ago
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2 years ago
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dybincka [34]
2/5 + 1/2

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= 4. Then 2 goes 5 times into
10 then multiply by 1 = 5.

Therefore the sum of 2/5 + 1/2 =9/10
5 0
3 years ago
Read 2 more answers
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