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Alex Ar [27]
4 years ago
7

Which set of integers is a pythagorean triple?

Mathematics
1 answer:
OLga [1]4 years ago
5 0
H^2 = P^2 + B^2

a. 6^2 = 2^2 + 3^2
36 = 4 + 9
36 = 13
Therefore this is not a Pythagorean triple

b.5^2 = 4^2 + 3^2
25 = 16 + 9
25 = 25
Therefore this is a phythagorean triple
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Find all solutions and write the answer in a general form. 6 sec2(x) − 6 = 0
Afina-wow [57]

Answer:

x = pi n

Step-by-step explanation:

6 sec^2(x) − 6 = 0

Add 6 to each side

6 sec^2(x) − 6+6 = 0+6

6 sec^2(x)=6

Divide by 6

 sec^2(x)  = 1

Take the square root of each side

sqrt(  sec^2(x) ) = ±sqrt(1)

 sec(x)  =± 1

sec (x) = 1       sec(x) = -1

Take the inverse sec of each side

sec^-1(sec (x)) = sec^-1(1)       sec^-1(sec (x)) = sec^-1(-1)

x = 2 pi n                                    x = pi + 2 pi n   where n is an integer

Combining

x = pi n

 

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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vitfil [10]
Step by step:

3 x 9/10
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