Step-by-step explanation:
the picture includes the answer and work
I plugged in 2 for x
the equations that got the same answer, I put together
174/29 = 6 times the difference
17*6 = 102
12*6= 72
34*6 =204
15*6 = 90
so the answer is A
One and a fourth bags of popcorn
We need the length, the width and the height
Kepler's third law described the relation between semi-major axis (or average distance to the star) and
the orbital period (how long it takes to complete one lap) as follows:
a^3 / p^2 = constant
In the case of our Solar system the constant is 1
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU
Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
