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shutvik [7]
3 years ago
5

Simplify 14 divided by 2 + 5 •4

Mathematics
2 answers:
bija089 [108]3 years ago
8 0

Answer:

27

Step-by-step explanation:

A-P-E-X

BigorU [14]3 years ago
7 0
14 divided by 2 plus 5 multiplied by 4 equals 28! use pemdas :D
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50 pts please help asap (:
andriy [413]

Answer:

d. 8 units

Step-by-step explanation:

If AC = 16 units then the length of CB is 8 units because DB is perpendicular bisector from the centre of circle.

3 0
3 years ago
You purchased a smartphone using your Visa® credit card. Your Visa has a monthly finance charge of 2.5% beginning the first of t
polet [3.4K]
Answer is a idk the math teacher is not a teacher or teacher that she is going through so I am going
3 0
3 years ago
16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.
Yuki888 [10]

Answer:

W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}

Observe that if the vector x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right] is in W then it satisfies:

\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]

This means that each vector in W can be expressed as a linear combination of the vectors \left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]

Also we can see that those vectors are linear independent. Then the set

\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\} is a basis for W and the dimension of W is 2.

7 0
3 years ago
On a 1/6 scale drawing of a bike, one part is 3 inches long. how long will the actual bike part be?
aniked [119]
1/6*6 is 1, so we can say that 3*6 is 18.
So, the part will be 18 inches in real life.
3 0
3 years ago
Read 2 more answers
Can someone answer these please !!!!!!
katen-ka-za [31]
A. m^2 - 36 = 0
m^2 = 36
m = √36 = 6 or -6

b. 3x^2 + 15 = 0
3x^2 = -15
x^2 = -5
x = √(-5) not possible unless complex numbers is applied
-1 = i^2
x = √(-5) = √(5i^2) = √5i

c. 4d^2 + 16 = 16
4d^2 = 0
d^2 = 0
d = 0


Hope it helped!
4 0
3 years ago
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