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andrey2020 [161]
3 years ago
14

Need help please on this please

Mathematics
1 answer:
svp [43]3 years ago
3 0
Really blurry maybe try to post it again
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NO IDEA HELP PLS SO CONFUSING
Hunter-Best [27]

Answer:

1. slope formula?

2. (0,6)

3. y= -3x+6

Step-by-step explanation:

because the original formula to make a like is y=mx+b.

just plug the values you have into the equation knowing that m is the slope and b is the y intercept.

the slope would be rise/run which in this case the rise is -6 and the run is 2.

so m= -6/2 = -3

and b = 6 because x is 0 when y is 6 for this graph.

(btw I put -6 as the rise because you are going down 6 units instead of going up)

4 0
3 years ago
This is a example ^^^
marshall27 [118]

Answer:

Step-by-step explanation:

It is a right triangle as it has a right angle (you can draw a little square to show that).

It's side are already recorded, so I tried my best, though I'm not sure it's correct.

Hope that helps!

4 0
3 years ago
Can you solve for a, b and c?<br> 2a – 3b = -5<br> 4a + 3b = 17<br> 5c - 2a = 1
MaRussiya [10]
Pills abs poisoned by a girl with you a
3 0
4 years ago
Suppose y varies directly with x and inversely with z. When x= 65 and z=5​, then y= 26. Find the constant of variation and the e
Doss [256]

Answer:y = 65x/z

Step-by-step explanation:

Suppose y varies directly with x and inversely with z. It means that as y increases or decreases, y increases or decreases while z decreases or increases respectively.

In order to remove the variation symbol and replace with an equation symbol, we would introduce a constant of variation, k. It becomes

y = kx/z

When x= 65 and z=5​, then y= 26. We would substitute these value to get the constant of variation, k. It becomes

26 = 65k/5

65k = 65

k = 1

The equation of combined variation will be

y = 65x/z

6 0
3 years ago
Calculate the length of this unknown side of the right angled triangle
Alenkasestr [34]

Answer:

a*2+ b*2 =c*2

Step-by-step explanation:

9*2 + b*2 = 17*2

b*2 = √(17*2 -9*2)

b =14.4 cm

7 0
3 years ago
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