Answer:
Altogether they lost 150 pennies.
Step-by-step explanation:
X = Dante's pennies
Y = Mia's pennies
X + Y = 350 1/2 X = 2/3 Y
X = 4/3 Y
4/3 Y + Y = 350
7/3 Y = 350
Y = 350 * 3/7
Y = 50 * 3
Y = 150
X + 150 = 350
X = 200
1/2 * 200 = 2/3 * 150
100 . = 100
1/2 * 200 = 100 -> Dante lost 100 pennies
1/3 * 150 = 50 -> Mia lost 50 pennies
Altogether they lost 150 pennies.
Volume of a cube with side lengths of 2, 2, and 2.
2³=8 m³
Volume of a cube with 4,4, and 4
4³=64 m³
Conclusion: The volume would be squared, or square rooted, depending on which way you are going.
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
Answer:
D
Step-by-step explanation:
D includes all possible outcomes.
