Given that:
Consider it is instead of 10 on two places.
is between 3 and 4. So, Beau thinks a good estimate for
is = 3.5.
Solution:
To find , Beau found 3² = 9 and 4² = 16.
He said that since 10 is between 9 and 16.
Since 10 is close to 9, therefore must be close to 3. So, Beau's estimate is high.
Now,
Since, 10 lies between 9.61 and 10.24, therefore must be lies between 3.1 and 3.2.
Therefore, the estimated value of is 3.15.
Answer:
15 is the total number of animals for which (p ∨ q) ∧ r true.
Step-by-step explanation:
From the diagram it is clear that
p contains {2, 5, 8, 9}
q contains {2, 4, 7, 5}
r contains {2, 4, 6, 9}
p ∨ q is the union of p and q which include all the animals which are in p, in q, or in both p and q.
Note: p ∨ q can not have duplicate animals
So,
p ∨ q = {2, 4, 5, 7, 8, 9}
(p ∨ q) ∧ r contains the animals which need to be common in both (p ∨ q) and r.
As
p ∨ q = {2, 4, 5, 7, 8, 9}
r = {2, 4, 6, 9}
So,
(p ∨ q) ∧ r = {2, 4, 9}
As
Therefore, 15 is the total number of animals for which (p ∨ q) ∧ r true.
Keywords: union, and operation, or operation
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