Answer:
B = 12.8 cm (to 1.d.p)
D = 24.1 cm (to 1.d.p)
Step-by-step explanation:
Using Pythagoras Theorem:
B: 4^2 + 3.5^2 = 28.25
square root 28.25 = 5.3 (to 1 decimal place) so this is the length of the missing side.
To find perimeter add sides a, b and c so...
perimeter of triangle B = 12.8 cm (to 1 decimal place)
D: 10^2 - 6.5^2 = 57.75
square root 57.75 = 7.6 (to 1 decimal place) so this is the length of the missing side.
To find perimeter add sides a, b and c so...
perimeter of triangle D = 24.1 cm (to 1 decimal place)
^2 indicates squared
Sorry but I'm not too sure / confident about A or C
Like terms would be taking all of the ones with a and getting them alone, all of the ones with b alone, and all plain numbers alone to simplify
1) 2a+3-5a+8b
****= -3a+8b+3****
take 2a-5a and that is your answer
2) 6a+rs-4a+6rs
=2a+rs+6rs
combine the a's 6a-4a
****=2a+7rs****
1rs+6rs combine rs's and that's it :)
**** is the answers
For line A,
if we increase x by 1 unit then y increases by 4 units i.e. (1,3) and similarly another point becomes
(2,7).
For line B,
if we increase x by 1 uni then y also increases by 1 unit i.e ( 1,1) and similarly another points becomes (2,2),(3,3),(4,4), etc.
For line C,
if we increase x by 3 units then y increases by 1 units i.e.(3,1) and similarly another points becomes
(7,2) and so on.
In above lines, the value of x is exactly equal to that of y in line B.
therefore, line B has constant proportionality between x and y.
Answer:
6 3/8
Step-by-step explanation:
Convert the fractions so that the denominators match.
, then 

, then 
Add up the fractions.


above is the distance formula, plugging your numbers from P(x1,y1) and Q(x2,y2).

or