Solve for x. 23=79(6x−36)+9 Enter your answer in the box. x =

you put $634 into an investment at 6% compounded annually for six years. what will be the balance be at the end of six years?

Norma-Jean [14]

Answer:

The answer would be the following amount $907.92

7 0

3 years ago

Read 2 more answers

Express 5×-4y=20 in the form a×+by+c=0and write the value of a,band c

finlep [7]

Answer:

a = 5

b = -4

c = -20

Step-by-step explanation:

Here, we want to express the given equation in the following form;

So we can have this as;

5x-4y-20 = 0

That means we have;

a as 5

b as -4

and c as -20

4 0

3 years ago

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

4 0

3 years ago

A rectangular prism has a base with a length of 25, a width of 9, and a height of 12. A second prism has a square base with a si

RSB [31]

Answer:

The height of the second prism is 12 units.

Step-by-step explanation:

First, we must know that the volume of a rectangular prism is equal to length x width x height. With this information, we can multiply the given dimensions of the first rectangular prism to get a volume of 2700 cubic units. From here, we must understand wha we need from the second rectangular prism. Because it has a square base of 15, that accounts for both its width and length. Therefore, we have that

$Volume= 15^2 x\\2700/225=x\\12=x$

6 0

2 years ago

If a data value in a normal distribution has a negative z-score, which of the following must be true?

Tamiku [17]

The data value must be less than the mean.

4 0

3 years ago

Read 2 more answers