Answer:
y intercept is 140, slope is 2/1
Step-by-step explanation:
sorry, not sure about the function
Note that
in the given closed interval, so the area is exactly given by the definite integral
(no absolute values needed!)
Integrating gives
<h2>9.</h2><h3>Given</h3>
<h3>Find</h3>
- linear approximation to the volume when the radius increases 0.4 cm
<h3>Solution</h3>
The equation for volume of a sphere is
... V = (4/3)π·r³
Differentiating gives
... dV = 4π·r²·dr
Filling in the given numbers gives
... change in volume ≈ 4π·(15 cm)²·(0.4 cm)
... = 360π cm³ ≈ 1130.97 cm³ . . . . . . volume of layer 4mm thick
<h2>11.</h2><h3>Given</h3>
- an x by x by 2x cuboid with surface area 129.6 cm²
- rate of change of x is 0.01 cm/s
<h3>Find</h3>
<h3>Solution</h3>
The area is that of two cubes of dimension x joined together. The area of each such cube is 6x², but the two joined faces don't count in the external surface area. Thus the area of the cuboid is 10x².
The volume of the cuboid is that of two cubes joined, so is 2x³. Then the rate of change of volume is
... dV/dt = (d/dt)(2x³) = 6x²·dx/dt
We know x² = A/10, where A is the area of the cuboid, so the rate of change of volume is ...
... dV/dt = (6/10)A·dx/dt = 0.6·(129.6 cm²)(0.01 cm/s)
... dV/dt = 0.7776 cm³/s
By finding the scale factor, we will see that the volume of the smaller solid is 86.75 m³.
<h3>
How to get the volume of the smaller solid?</h3>
If the solids are similar, then there is a scale factor between the two. Then the relation between the areas is equal to the scale factor squared, and the relation between the volumes is equal to the scale factor cubed.
This means that if the areas are 169 m² and 81 m², then we can write:
169 m² = (k²)*81 m²
Solving for k, we get:
k = √(169 m²/81 m²) = 1.44
Then if the volume of the large solid is 124.92m³ we can write:
124.92m³ = k³*V
Replacing k and solving for V we get:
124.92m³ = (1.44)³*V
(124.92m³/ (1.44)³) = V = 86.75 m³
If you want to learn more about scale factors:
brainly.com/question/3457976
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