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Marianna [84]
3 years ago
5

PLEASE PLEASE HELP I WILL GIVE BRAINALSIT

Mathematics
1 answer:
Virty [35]3 years ago
6 0

Answer:

$33 for 11 packs of paper

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Pythagorean theorem calc: find c, a=12.96148, b=11
eduard
A = 12.96148 b = 11
a^2 + b^2 = c^2
(12.96148)^2 + (11)^2 = c^2
168 + 121 = c^2
289 = c^2
c = sqrt(289)
c = 17 I did a little bit of rounding to get this, but I'm sure it is close enough.
3 0
3 years ago
Which statement could be used to explain why f(x) = 2x - 3 has an inverse relation that is a function
Virty [35]

Answer:

are there answer chart?

Step-by-step explanation:

4 0
4 years ago
Solve for X -6.9<8.1-1.5x
notka56 [123]

Step-by-step explanation:

-6.9<8.1-1.5x

-9.6-8.1<-1.5x

-15<-1.5x

-1.5x>-15

x>10

8 0
3 years ago
Find the coefficient of the 4th term in expansion of (x +2 )^5
LuckyWell [14K]
(x + 2)^5=(x+2)^2\cdot{(x+2)^2}\cdot{(x+2)}\\\\(x+2)^5=(x^2+4x+4)\cdot{(x^2+4x+4)}\cdot(x+2)

(x+2)^5=(x^4+8x^3+24x^2+32x+16)\cdot(x+2)

(x+2)^5=x^5+10x^4+40x^3+80x^2+80x+32

10

6 0
3 years ago
The polar form of this is?
prohojiy [21]

Answer:

2, 120 degrees

Step-by-step explanation:

The first step in finding the polar form is finding the modulus, r

r= sqrt( x^2 + y^2)

r = sqrt( (-1)^2 + sqrt(3)^2)

r = sqrt(1+3)

r= sqrt(4)

r =2


The next step is finding the angle

theta = arctan (y/x)

theta = arctan (sqrt(3)/-1))

theta = arctan (-sqrt(3))

theta = -60


The point (-1, sqrt(3)) is in the 2nd quadrant, but our angle is in the 4th quadrant, so we add 180 degrees

theta = -60 + 180 = 120

theta = 120 degrees

6 0
3 years ago
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