Kevin installed a certain brand of automatic garage door opener that utilizes a transmitter control with four independent switches, each one set on or off. The receiver (wired to the door) must be set with the same pattern as the transmitter. If six neighbors with the same type of opener set their switches independently.<u>The probability of at least one pair of neighbors using the same settings is 0.65633</u>
Step-by-step explanation:
<u>Step 1</u>
In the question it is given that
Automatic garage door opener utilizes a transmitter control with four independent switches
<u>So .the number of Combinations possible with the Transmitters </u>=
2*2*2*2= 16
<u>
Step 2</u>
Probability of at least one pair of neighbors using the same settings = 1- Probability of All Neighbors using different settings.
= 1- 16*15*14*13*12*11/(16^6)
<u>
Step 3</u>
Probability of at least one pair of neighbors using the same settings=
= 1- 0.343666
<u>
Step 4</u>
<u>So the probability of at least </u>one pair of neighbors using the same settings
is 0.65633
Answer:

Step-by-step explanation:
There are simply 5 possible values in the given set. Out of these, only one of these is the number 1. Therefore, the probability a 1 is drawn (P(1)) is
.
Answer:
gg
Step-by-step explanation:
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Using it's concept, it is found that the odds that the winner shops in the store 4 or more times a week are given by: 9:41.
<h3>What is the odd of an event?</h3>
It is given by the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
Researching the problem on the internet, it is found that 18% of the winners shop in the store 4 or more times a week, while 82% do not, hence:
18:82 = 9:41
The odds that the winner shops in the store 4 or more times a week are given by: 9:41.
More can be learned about odds at brainly.com/question/25683609