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Alex73 [517]
2 years ago
6

Given the following points, find the equation of the line. Then state the slope of a line

Mathematics
1 answer:
LenKa [72]2 years ago
5 0

Answer:

Step-by-step explanation:

the slope is -3/2

equation: y=-3/2x +4

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Which angles are alternate exterior angles?
omeli [17]
A. 2 and 8
It’s the pair of angles on the outer side of each of those two lines but on opposite of the transversal.
4 0
2 years ago
Please help me. X/6 ≥ 7. I also need to know how this would be graphed thank you.
BigorU [14]

Answer: The inequality solves to x ≥ 42

The graph is shown below

==================================================

Explanation:

We have some unknown number x, and we're dividing by 6 to form the fraction x/6. That result is 7 or larger which means we write x/6 ≥ 7

To solve for x, we undo the division. We'll multiply both sides by 6. That's how we get to x ≥ 42

The graph will involve a number line. Plot a closed filled in circle at 42 on the number line. Shade to the right. This visually represents any number that is 42 or larger. The endpoint 42 itself is included in the solution set.

Side note: We would use an open circle if we didn't have the "or equal to" portion for the inequality sign.

6 0
2 years ago
Read 2 more answers
Are these functional or non functional ?
svetoff [14.1K]

Answer:

Relation 3 is a function and Relation 4 is nog

6 0
3 years ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
Read 2 more answers
Given a soda can with a volume of 15 and a diameter of 2, what is the volume of a cone that fits perfectly inside the soda can?
Naddika [18.5K]
Check the picture below.

so, a cone, that fits inside the cylinder, will have the same height "h" and radius "r".  Thus


\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad \boxed{\pi r^2 h}=15
\\\\\\
\textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\implies V=\cfrac{\boxed{15}}{3}

8 0
2 years ago
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