2 years ago

Division of Labor:

1 answer:

ki77a [65]2 years ago

4 0

Answer:

Step-by-step explanation:

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barxatty [35]

Answer:

Step-by-step explanation:

212113

8 0

2 years ago

nexus9112 [7]

Center: 0,0
vertex: 5,0
vertex2 (-5,0)

4 0

2 years ago

Alexandra [31]

Answer:

Step-by-step explanation:

5+5+5+5+5+5+5+5+5+5+5+5

4 0

3 years ago

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago

oksano4ka [1.4K]

This is a lot of math to write.... so I'll just say the answer is -21 :D

8 0

3 years ago