Answer:
y=Ae^(1.25t)
Step-by-step explanation:
From the expression y=Ae^kt
After two days of the experiment, y = 49 million, t=2
After four days of the experiment, y= 600.25 million, t=4
A is the amount of bacteria present at time zero and t is the time after the experiment (in days)
At t=2 and y =49
49=Ae^2k…………….. (1)
At t=4 and y = 600.25
600.25=Ae^4k………… (2)
Divide equation (2) by equation (1)
600.25/49=(Ae^4k)/(Ae^2k )
12.25=e^2k
Take natural log of both sides
ln(12.25) =2k
2.505 =2k
k=1.25
The exponential equation that models this situation is y=Ae^(1.25t)
This isn't a question. What is the question?
Answer:
You would first put it into point slope form which is (y-y_1)=m(x-x_1). Then you would solve for y.
Answer:
-$100
Step-by-step explanation:
ive been where u were with that one question right or wrong...
im not to sure what the quesion is asking so maybe wait for someone else to say it too. mb if i got it wrong or sum.
good luck
