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2 years ago

Missing angle trig (inverse) 10th geometry HELP ASAP

Mathematics

1 answer:

USPshnik [31]2 years ago

7 0

Answer:

33. B

34. D

35. D

36. A

Step-by-step explanation:

All these questions require is a calculator :). For question 35, all you want to put in is arccos(0.8192) and make sure your calculator is in degree mode. For 36, all you want to put in is arctan(0.3839). For 34, all you want to put in is arcsin(0.6018). For 33, all you want to put in is arcsin(0.6561).

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Which expression is undefined?<br> ОА<br> A 0:6<br> B. 6:0<br> C-14:3<br> O 0 14 = (-3)<br> D

avanturin [10]

Answer:

Step-by-step explanation:

because it would have many solutions

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1 year ago

Evaluate the following expression. 6 squared -1

natita [175]

Answer:

Step-by-step explanation:

$6^2 - 1\\36-1\\35$

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2 years ago

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The function(t)--4.87+18.75 is used to model the height of an object projected in the air, where h() is the height in

NNADVOKAT [17]

The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.

<h3>How to calculate the domain of the function?</h3>

In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:

0= -4.87t² + 18.75t.

4.87t(-t + 3.85) = 0

t = 0 or t = 3.85.

Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).

<h3>How to calculate the range of the function?</h3>

h(t) = -4.87t² + 18.75t

h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)

h(t) = -4.87(t - 1.925)² + 18.05

Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).

Read more on domain here: brainly.com/question/17003159

#SPJ1

3 0

1 year ago

Read 2 more answers

I need help, this is geometry

Artemon [7]

Answer:

∠P = 39º

∠Q=120º

∠R = 21º

Step-by-step explanation:

m∠P+m∠Q+m∠R=180º (sum of ∠s in a triangle)

2x-3+6x-6+x=180º (substitution)

9x-9=180º (algebra)

9x=189º (algebra)

x=21º (algebra) (this is ∠R)

(2x-3)=39º (algebra) (this is ∠P)

6x-6=120º (algebra) (this is ∠Q)

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1 year ago

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a pyramid has a regular hexagonal base with side length of 4 and a slant height of 6. what is the total area of the pyramid

Stels [109]

So hmm notice the picture below

the pyramid itself, is really, just one regular hexagon, at the bottom
and 6 triangles, stacked up at each other at the edges

now, if you just get the area of the regular hexagon, and the 6 triangles, add them up, that'd be the total surface area of the pyramid then
$\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}\cdot n\cdot s^2\cdot cot\left( \frac{180}{n} \right)\qquad 
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of a side}\\
\frac{180}{n}=\textit{angle in degrees}\\
----------\\
n=6\\
s=4
\end{cases}\\\\\\ A=\cfrac{1}{4}\cdot 6\cdot 4^2\cdot cot\left( \frac{180}{6} \right)$

now, for the triangles, well, area of a triangle is 1/2 bh, as you'd know, and you have both

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2 years ago